用C语言递归程序计算f(x.n)=x-x^2 -- (-1)^(n-1)*x^n

#include"stdio.h"intgys(intm,intn){if(n>1){if(m%n!=0){returngys(n,m%n);}elsereturnn;}}intmain(){intm

只要将前面那个程序的fun函数中,i改成从1开始循环就行了.#includeintpower(intx,intn)//power函数{intp=1,i;for(i=1;i

#includeunsignedintFibonacci(intn);intmain(void){inti;for(i=1;i

#includefun(intx,intn){if(n==0)return(1);elsereturn(x*fun(x,n-1));}main(){intx,n;scanf("%d,%d",&x,&n

#includeintfun1(intn){intsum=1;for(inti=1;i

#include <stdio.h>int sumn(int n,int *flag){ (*flag)++; if(n==1)

这个东西关键是递归算法的确定,需要一点数学知识.#include//递归计算函数intcalc(intx){if(xif(x==1){return1;}elseif(x==2){return3;}el

longadd(intn){intt=n-1;if(t>1){longresult=n*t;longsum=result+add(t);returnsum;}else{returnn;}}楼上的方法,

#includedoubleH(intn,doublex){if(x>1){if(n==0)return1.0;//H0(x)=1;if(n==1)return2.0*x;//H1(x)=2x;//直

#include#includeintjiecheng(inte,intn){//intx=e;if(n==1)returne;else{returne*jiecheng(e,--n);}}intma

#include<stdio.h>int sum(int n){   return n>0?n+sum(n-1):0;}i

f函数里已经被传进一个参数值了为什么还要再输入一个n值呢?另外,n前还要加&,应该是scanf("%d",&n);

#include#includefloatmyfunction(intn,intx){if(0==n){return1;}elseif(1==n){returnx;}else{return((2*n-

longmi(intx,intn){if(n=1)returnn;elsereturn((long)x*mi(x,n-1);}

1.#include"stdio.h"//#defineRECURSION1#ifdefRECURSIONlongfact(intn){if(n

原理是一样的,可以参考下面的稍微改一下,自己动手可以学的更多,#include//实现数据的全排序voidswap(int*a,intx,inty)//数据交换{inttemp=a[x];a[x]=a

#include#includefun(intx);intmain(void){char*pszBuff=NULL;inta;inti=1;intsumResult=0;printf("inputai

#includevoidmain(){intn=1,N,i;scanf("%d",&N);if(N20)printf("shuruwuxiao!\n");else{for(i=1;i

intN(intx){if(x==0){return1;}else{returnx*N(x-1)}}intiRet=0;for(inti=1;i

不懂为什么要分奇数偶数 下面是我编的 你可以试试!#include "stdio.h"long power(int x,int&n