f-1(x)求导
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有点慢你能等等吗?再答:
f'(x)=(1-cosx)'sinx+(1-cosx)(sinx)'=[1'-(cosx)']sinx+(1-cosx)cosx=sin²x+cosx-cos²x=cosx-co
y=f(x)=(1+1/x)^x两边取自然对数得lny=xln(1+1/x)两边求导(1/y)*y'=ln(1+1/x)+[x/(1+1/x)]*(1+1/x)'y'/y=ln(1+1/x)+[x&s
f(x)=(x-1)(x-2)(x-3)f'(x)=(x-2)(x-3)+(x-1)(x-3)+(x-1)(x-2)=x^2-5x+6+x^2-4x+3+x^2-3x+2=3x^2-12x+11
f(x)=2x/x^2+1是f(x)=2x/(x^2+1)的意思噻?f′(x)=[2(x^2+1)-2x*2x]/(x^2+1)^2=(2-2x^2)/(x^2+1)^2u/v求导为:(u′v-uv′
f(x)=x(1-x^2)那么导数为f'(x)=x'(1-x^2)+x(1-x^2)'=1-x^2+x*(-2x)=1-x^2-2x^2=1-3x^2
f'(x)=1-(1/2)/√(1-x)祝你开心!希望能帮到你,如果不懂,请追问,祝学习进步!O(∩_∩)O
再问:或字后面的过程可不可以详细点?再问:(-1)是怎么来的?再答:再答:再答:复合函数的求导法则再问:(⊙o⊙)哦谢谢再答:第一种比较好理解……
f(x)=(e^x+1)/e^x=1+1/e^x=1+e^(-x)f'(x)=[1+e^(-x)]'=[e^(-x)]'=[e^(-x)]*(-x)'=[e^(-x)]*(-1)=-e^(-x)=-1
f(x)=ln(x+√1+x^2)f'(x)=1/(x+√(1+x^2)*(x+√1+x^2)'=1/(x+√(1+x^2)*(1+(√1+x^2)'=1/(x+√(1+x^2)*(1+1/2*√(x
y'=-1/x^2
f(x)=(x^n-1+1)/(1-x)=-[1+x+x^2+.+x^(n-1)]+1/(1-x)n阶导数,前面这项为0看后面f^n(x)=(1-x)^(-n-1)
f'(x)=lnx+(x+1)/x-1=lnx+1/x
(uv)'=u'v+v'uf'(x)=ln(x+1)+1
f(x)=(2x+1)(x-1)=2x^2-2x+x-1=2x^2-x-1f'(x)=4x-1
f'(x)=[(1+x)/(1-x)]'e^(-ax)+(-ae^-ax)[(1+x)/(1-x)]=[(1+x)/(1-x)]'e^(-ax)-ae^(-ax)*(1+x)/(1-x)=[-(x-1
y'=f'(arcsin1/x)*(arcsin1/x)'=f'(arcsin1/x)*1/√(1-1/x^2)*(1/x)'=-f'(arcsin1/x)*1/√(1-1/x^2)*1/x^2
f(x)=(xlnx)^(-1)所以f'(x)=-1*(xlnx)^(-2)*(xlnx)'(xlnx)'=x'lnx+x*(lnx)'=lnx+x*1/x=lnx+1(xlnx)^(-2)=1/(x
y=f(1/x)y'=f'(1/x)*(1/x)'=-f'(1/x)/x^2
一般的[f(x)/g(x)]'=[f'(x)g(x)-f(x)g'(x)]/[g^2(x)]所以对本题目f'(x)=[e^x*(x-1)-e^x*1]/(x-1)^2=e^x*(x-2)/(x-1)^