求解2x的三次方乘以y减去二分之一xy的三次方-搜答案-智慧作业帮

(-1/2*xy²)³-1/6*x(xy³)²=-1/8*x³y^6-1/6*x³y^6=-7/24*x³y^6

(-1/2*X^2*Y^3)*2^4*X^5*Y^5=(-1/2*2^4)*X^(2+5)*Y^(3+5)=-8X^7Y^8

(-1/2乘x^2乘y^3)乘2^4乘x^5乘y^5=-8乘x^7乘y^8

一又二分之一乘以[三乘以(负三分之二的二次方)]减去三分之一乘以负二的三次方减去二十=3/2×(3×4/9)-1/3×(-8)-20=2+8/3-20=-15又1/3

(x-y）³×（x-y）²×（y-x）=（x-y）³×（x-y）²×[-(x-y)]=-（x-y）的6次方

[(1/2)^2]^3×(2^3)^2=(1/2)^6×2^6=(1/2×2)^6=1^6=1

=-xy/2*(4x²-4xy+y²）=-xy/2*(2x-y)²

3/2＋2m-1＝0m＝-1/4

原式=4(x-y)^3*(-1/8)(x-y)^6=-(1/2)(x-y)^9

由已知x=√3－2得所以x+2=√3所以x2+4x+4=3所以x2+4x=－1X4+4x3+3x2+8x－4=(X4+4x3)+(3x2+12x)－4x－4=X2(x2+4x)+3(x2+4x)－4x

(x-2y)2*(2y-x)3=(x-2y)2*(2y-x)2*(2y-x)=(x-2y)2*(x-2y)2*-(x-2y)=-(x-2y)5结果等于－(x-2y)的5次方

因为单项式3X的n＋1次方乘以y的4次方与二分之一X的三次方乘以y的m-2是同类项则有;n+1=3,N=2m-2=4,M=6代数式3.5n的平方m+2nm-2分之7mn的平方+3mn的值=3.5n^2

x^3-y^3=x^3-x^2y+y^2x-yx^2+xy^2-y^3=x^2(x-y)+xy(y-x)+y^2(x-y)=(x-y)(x^2-xy+y^2)

[-2(X-Y)]的四次方×[二分之一(Y-X)]的三次方=16(x-y)的四次方×[-1/8(x-y)的三次方]=-2(x-y)的七次方

两边同除以x^2y'/(x^2)-(2/x^3)y=x通分(xy'-2y)/(x^3)=x[y/(x^2)]'=x积分y/(x^2)=(1/2)x^2+Cy=(1/2)x^4+Cx^2再问：请问，最终

求后面的那串没看懂,但根据上面提到的同类项可算出n=2m=6把这个代到让你求的分式里面就可得到答案了

(-2x^my^3)*(3x^3*y^2)*(5x^2y^n)=-30x^4y^3-30x^(m+3+2)y^(3+2+n)=-30x^4y^3m+3+2=4m=-13+2+n=3n=-2

0.4x²y乘以（二分之一xy）²-（-2x）的三次方乘以xy的三次方=0.4x²y*1/4*x²y²+8x³*xy³=0.1x^

-(x-y)^10那位错了吧如果有什么不懂的,欢迎继续问我来自“理科最强”团队