作业帮求满足1*2 2*2语句·
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/14 20:06:10
需要的控件：命令按钮,2个,command1,command2标签,2个,label1,label2command1代码：Private Sub Command1_Click()&
Dimi,nasIntegerDimsasdoublen=val(Text1.Text)i=(1)s=0DoUNTILi>(2*n-1)s=(i+s)i=i+（2）LoopText2.text=(s)
PrivateSubForm_Click()DimnAsLong,m,k,jAsLong,iAsLongOnErrorGoToerrn=InputBox("请输入一个整数：")m=0Forj=1Ton
#include"stdio.h"voidmain(){intn=1,sum=0;while(sum
//while写法#include <stdio.h>main(){ long total=1, i=1;&nb
DECLARE@nINT,@sumINTSET@sum=0SET@n=1SET@sum=@sum+@nWHILE(@sumBEGINSET@n=@n+1SET@sum=@sum+@nENDPRINT(
整理第一式得7x
将原式22x+2-22x+1=32，化成同类项 即2×22x+1-22x+1=32 可得22x+1=32 &n
2(5x+1)/3-x再问：-14/5还有-1.-2啦再答：的非负整数解
用什么语言,能用函数调用吗,还是只用for语句再问：给个答案怎么都成谢谢了再答：#include#includeusingnamespacestd;intmain(){unsignedintsum=0
望采纳!#include<stdio.h>#include<stdlib.h>intmain(void){ intcnt=0; in
intsum=0;inti=0;while(i
OptionExplicitPrivateSubCommand1_Click()DimiAsIntegerDimjAsIntegerDimmAsIntegerm=Val(InputBox("输入m的值
满足条件1走语句1不满足走语句2这个是毋庸置疑的
inttotal;for(i=1;i
PrivateSubCommand1_Click()Dimm%,n%Fori=1To100IfiMod3=0Thenm=m+1IfiMod7=0Thenn=n+1NextiPrint"统计1~100中
sets:r/1..100/:;endsetscalc:sum=0;@for(s(i):sum=sum+i);endcalc单用sum函数sets:r/1..100/:;endsetssum=@sum
α∈(π/3,5π/6]
Basic：PrintInt((11*Sqr(33)-1)/2)
#include<stdio.h>voidmain(){inti,k=0;for(i=1;i<=1000;i++){if(i%7==2&&i%5==3&&i%3==2){printf