求y∧2-2xy 3=0的导数
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y'=4x-1/x=0x=1/2x=-1/2舍去当00函数单增
x³y+2x²y²+xy³=xy(x²+2xy+y²)=xy(x+y)²=-1*2²=-4
y=2x的导数不是应该是2嘛……
y=lntan(x/2)e^y=tan(x/2)e^yy'=0.5sec²(x/2)=0.5/cos²(x/2)y'=1/[2cos²(x/2)tan(x/2)]=1/[
x3y+2x2y2+xy3=xy(x2+2xy+y2)=xy(x+y)2,∵x+y=5,∴(x+y)2=25,x2+y2+2xy=25,∵x2+y2=13,∴xy=6,∴xy(x+y)2=6×25=1
两边分别求导,得(2y)'=(-1+xy^3)'2y'=(xy^3)'2y'=x'y^3+x(y^3)'(uv)'=u'v+uv'2y'=y^3+x*3y^2*y'2y'=y^3+3xy^2*y'
∵x+y=4,∴(x+y)2=16,∴x2+y2+2xy=16,而x2+y2=14,∴xy=1,∴x3y-2x2y2+xy3=xy(x2-2xy+y2)=14-2=12.
y^5+2y-x=0求关于y的导数这是隐函数,两端对x求导:5y^4y'+2y'-1=0所以(5y^4+2)y'=1y'=1/(5y^4+2)
z=2x²+3xy+y²∂z/∂x=4x+3y∂z/∂y=3x+2y∂²z/∂x²=4&
x3次方y-2x2y2+xy3=xy(x²-2xy+y²)=xy(x-y)²=3x3²=27如果本题有什么不明白可以追问,再问:=xy(x2-2xy+y2)=x
y‘=[sin²(cos3x)]'=2sin(cos3x)×[sin(cos(3x))]'=2sin(cos3x)cos(cos(3x))(cos3x)'=sin[2(cos3x)]×(-s
求一次导=(x'*lnx-x*(lnx)')/ln^x=(lnx-1)/ln^x然后再次求导=[(lnx-1)'*ln^x-(lnx-1)*2lnx/x]/(lnx)^4=[ln^x-2lnx(lnx
已知x+y=5,xy=3,代数式x3y-2x平方y平方+xy3=xy(x²-2xy+y²)=xy(x-y)²=3×[(x+y)²-4xy]=3×(25-12)=
∵|x+y+1|≥0,|xy-3|≥0|x+y+1|+|xy-3|=0,∴x+y+1=0,即x+y=-1xy=3xy3+x3y=xy(x²+y²)=yx[(x+y)²-2
x+y=4,xy=2后者平方后二式相加再加后者平方
x3y+xy3=xy(x^2+y^2)=(√3-√2)(√3+√2)((√3-√2)^2)+(√3-√2)^2)=1*(3-2√6+2+3+2√6+2)=10
∵x-y=l,xy=2,∴x3y-2x2y2+xy3=xy(x2-2xy+y2)=xy(x-y)2=2×1=2.
y=(sin2x)^2y'=2sin2x(sin2x)'=2sin2xcos2x(2x)'=4sin2xcos2x=2sin4x再问:=2sin2x(sin2x)'怎么来的呀再答:复合函数求导法则[f
错了吧,x³+y是x³yx+y=2√7xy平方差=7-3=4则(x+y)²=x²+2xy+y²=(2√7)²x²+y²=