求xy=3,y+x=4所围成的平面图形面积
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1/y-1/x=5所以:x/xy-y/xy=5即是:(x-y)/xy=5x-y=5xy(2x+4xy-2y)/(x-3xy-y)=((2x-2y)+4xy)/((x-y)-3xy)=(2*5xy+4x
xy/(2x+y)-xy/(2x-y)=3xy/(2x-y)+xy/(2x+y)=4;一、两公式对加得2xy/(2x+y)=7xy=(2x+y)*7/2二、把xy代入原公式求解就行了:(2x+y)*7
siny+e²-xy²=0,两边对x求导(cosy)(dy/dx)-y²-2xy(dy/dx)=0∴dy/dx=y²/(cosy-2xy)先求y²=2
根据题意得:分母:x+y+2xy=3xy+2xy=5xy分子:2x+2y-xy=2×3xy-xy=6xy-xy=5xy∴值为5xy分之5xy即为1
x^+2xy+y^+4=16(x+y)²=16-4=12(1)x^-2xy+y^=16(x-y)²=16(2)(1)-(2)2y*2x=-4xy=-1(3xy+6y^)+|x^-(
因为x-y=4xy所以x-2xy-y=2xy2x+3xy-2y=11xyx-2xy-y分之2x+3xy-2y=5.5
y=1/x当y=3时,x=1/3S=∫(1/3—2)1/xdx=lnx|(1/3—2)=ln2-ln(1/3)=ln6
(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-6xy+3x-3y=-6×(-2)+3×1=15
原式=3x-3y-6xy=3-12=-9
令y/x=m,xy=n则积分区域为1
再问:帅再问:谢了再答:过奖了
(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-2xy+2x+3y-3xy-2y+2x-x-4y-xy=-6xy+3x-3y=-6xy+3*(x-y)当时,原式=-6*1+3*
(x+y)^+xy=16+2=18
4x²+8xy+9y²=2(2x²+xy)+3(3y²+2xy)=38.
这类题,先化简代数式为XY与X+Y的代数式,然后代入已知条件,就可以算出来.(3xy+10y)+[5x-(2xy+2y-3x)]=3XY+10Y+5X-2XY-2Y+3X=XY+8Y+8X=XY+8(
(3x-2y+8xy)-(x-4y-5xy)=3x-2y+8xy-x+4y+5xy=(3x-x)+(-2y+4y)+(8xy+5xy)=2x+2y+13xy=2(x+y)+13xy=2×3+13×(-
解x-3y=0x=3y(4xy)/(x²-y²)-(x+y)/(x-y)=(4xy)/(x+y)(x-y)-(x+y)²/(x-y)(x+y)=(4xy-x²-
(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-2xy+2x+3y-3xy-2y+2x-x-4y-xy=-6xy+3x-3y=-6*(-2)+3*1=15不懂可追问,有帮助请采