根号2-x十根号x-2-y二6,求yx的平方根

根号2x+根号3y=2根号6(1)根号3x-根号2y=1(2)(1)*√2+（2）*√3得5x=5√3x=√3把x=√3代入（2）得3-√2y=1y=√2∴x=√3,y=√2再问：谢啦

题是这样的吧：[(√x-√y)^3+2x√x+y√y]/(x√x+y√y)+[3√(xy)-3y]/(x-y)原式=[(x√x-3x√y+3y√x-y√y)+2x√x+y√y]/(x√x+y√y)+[

[(2/3)x√(9x)+6x√(y/x)]+[y√(x/y)-x²√(1/x)]化简：原式=[(2/3)*3*x√x+6√(xy)]+[√(xy)-x√x]=2x√x+6√(xy)+√(x

根号2x+根号3y=5(1)根号3x+根号2y=2根号6(2)(1)+(2)(√2+√3)x+(√2+√3)=5+2√6=(√2+√3)²所以x+y=√2+√3(3)(2)-(1)(√3-√

现在只能告诉你x=5-2根6y=5+2根6你求的东西不明了.、建议加上括号.

因为4x^2+9y^2-4x-6y+2=0,所以4x^2-4x+19y^2-6y+1=0,(2x-1)^2+(3y-1)^2=0所以2x-1=0,3y-1=0,所以x=1/2.y=1/3所以根号y/（

(x√x+x√y)/(xy-y^2)-[x+√(xy)+y]/(x√x-y√y)=[x(√x+√y)/[y(√x-√y)(√x+√y)]-[x+√(xy)+y]/{(√x-√y)[x+√(xy)+y]

（根号y/根号x-根号y)-(根号y/根号x+根号y)=｛根号y（根号x+根号y）｝/（x-y）-｛根号y（根号x-根号y）｝/(x-y)=(y+y)/(x-y)因为x=2y所以原式=2y/y=2

√(2x+6)+|y-√2|=0所以2x+6=y-√2=0所以x=-3,y=√2

原式=[(√x-√y)²+(√x+√y)²]/(√x+√y)(√x-√y)=(x+y-2√xy+x+y+2√xy)/(x-y)=2(x+y)/(x-y)=2(2+√3)/(2-√3

（（x-y)/(√x+√y))-(x+y-2√xy)/(√x-√y),分母有理化,第一个式子分母乘以√x-√y,又(x+y-2√xy)=(√x-√y)(√x-√y),所以原式等于√x-√y-（√x-√

你的x、y分大小写吗?2Xy/x根号y什么意思?再问：没大小就是xyx十Y/（根号x十根号y）十2Xy/（x根号y十y根号x）再答：Y/（根号x十根号y）这一项分子分母都乘以（根号x-根号y）；2Xy

原式=√y/(√2y-√y)-√y/(√2y+√y)=√y/[√y(√2-1)]-√y/[√y(√2+1)]=1/(√2-1)-1/(√2+1)=(√2+1)/(√2+1)(√2-1)-(√2-1)/

a+b-2010和2010-a-b互为相反数所以都得0等式右边为零左边两个非负数相加得零两式都为0即：根号3x+6+根号2y+7=0得：3x+6=0,2y+7=0x=-2,y=-7/2√(xy)=±√

可知x≥0,y≥0(x-y)/(√x+√y)-(x-2√xy+y)/(√x-√y)=(√x+√y)(√x-√y)/(√x+√y)-(√x-√y)²/(√x-√y)=(√x-√y)-(√x-√

√x(√x-√y)=3√y(5√y-√x)(√x)^2-√xy=15(√y)^2-3√xy(√x)^2+2√xy-15(√y)^2=0因式分解得：(√x+5√y)(√x-3√y)=0所以：√x+5√y

[x+2√(x-1)]=[√(x-1)+1]^2[x-2√(x-1)]=[√(x-1)-1]^2x-1>=0x>=1y=√[x+2√(x-1)]+√[x-2√(x-1)]=√(x-1)+1+｜√(x-

原式=5|x|√(xy)-2y*√(xy)/|x|-6x√(xy)/|x|=(5|x|-2y/|x|-6x/|x|)*√(xy)