c语言输入一个正整数n,输出0-n之内的所有奇数.

#include"stdio.h"intmain(){\x09inti,j,n;\x09inta[12];\x09intmin,mx;\x09scanf("%d",&n);\x09for(i=0;i

intmain(intargc,char*argv[]){intinput;intret,num;printf("Inputaint:");scanf("%d",&input);for(;;){num

#includevoidmain(){\x09intn,i,j,t,a[10000];\x09printf("请输入正整数N:");\x09scanf("%d",&n);\x09printf("请依次

#includevoidmain(){inti,N,sum;while(scanf("%d",&N)){sum=0;for(i=1;i

#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}

#includemain(){intn,c=0;printf("输入一个小于等于一万的整数：");scanf("%d",&n);if(n>10000&&n

#include<stdio.h>int main(){    int n;    do

只学循环完全可以办到,关键是要动脑啊#includevoidmain(){\x09intn,m,max,i;\x09max=0;\x09printf("PleaseInputANumber:\n");

#include <stdio.h>void main (){ int a[10]; int i,k=0,n,min,

#includeintmat[10][10];voidmain(){intn,i,j;intok=1;scanf("%d",&n);for(i=0;i

#include#includevoidmain(){intn;printf("pleaseinputn:");scanf("%d",&n);inti,j,sum;for(i=1;i

#includevoidmain(){\x09inti,n;\x09inta[10];\x09ints,p;\x09printf("n:");\x09scanf("%d",&n);\x09for(i=

使用了数组的动态分配,看不懂的话我还有其他方案#include#includeboolprime(intnum){boolflag=true;if(num

vari,j,n:longint;z:boolean;beginreadln(n);writeln(2);fori:=3tondobeginz:=true;forj:=2toi-1doifimodj=

#includemain(){inti,j,N,t,k=0;intscore[100];printf("请输入整数的个数N：\n");scanf("%d",&N);printf("请输入N个整数：\n

#includemain(){intn,sum=0;scanf("%d",&n);for(inti=0;i

#includeintmain(void){intn=0,m=0,i=0,j=0,k=0;scanf("%d",&n);while(n--){\x09scanf("%d",&m);\x09for(j=

第一个for(i=0;i

#includemain(){intn,i,j;printf("inputainteger:");scanf("%d",&n);printf("\n");for(i=1;i

#include#defineNUM20voidmain(){longn;intdata[NUM]={0},len=0;scanf("%d",&n);do{data[len++]=n%10;n/=10