c语言编写程序函数,计算 s=6! 10! 22!-搜答案-智慧作业帮

#include"stdio.h"voidfun(intn,intk){intj;doublesum=0;for(j=1;j

//别说100位,1000位都没问题,给你个例子.#include#definePRECISION2800#defineFRACTION1000#defineGROUP4#defineINITIALV

题1:

#includemain(){doublex,y;scanf("%lf",&x);if(x

#includeintmain(void){intn;inti,j;floatsum=1.0;floatdex=1.0;printf("输入一个数：");scanf("%d",&n);for(i=2;

TCHARszBuff=newTCHAR[10000];这里把所有的内容放到szBuff里intaverage,iWordNum,iLine;while(*szBuff++!='\0'){if(*sz

#includeintmain(void){intn=0,i=0;doublep=1,q=0,s=0;printf("n=");scanf("%d",&n);for(i=1;i

#includeintfact(intn){if(n==0||n==1)return1;elsereturnn*fact(n-1);}intmain(){printf("5!+10!=%d\n"

#includevoidmain(){doubler,s,l;printf("请输入圆的半径\n");scanf("%lf",&r);s=3.14159*r*r;l=2*3.14159*r;print

#include <stdio.h>int main(){ float x, tax = 0;

#includeintmain(void){inti=1,s=0;while(i

你好.代码如下：#include<stdio.h>#include<stdlib.h>intmain(intargc,char*argv[]){doubles=0.00;/*总

6题：//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){doubles,tmp;intx;for(s=0,tmp=x

因为3个加法的运算规律是相同的,使用一个函数来计算循环值#includeintfun(intn)//计算累加结果函数{//这里还可以判断下n是否小于等于0intsum=0;inti;for(i=1;i

main(){inta,b,c;//a是输入测试值,b是分段值,c是条件标志printf("inputthevalueandpercentils:\n");scanf("%d%d",&a,&b);//

编写程序,计算S

;MOVAX,AANDAX,B;AX=aANDbMOVBX,AXORBX,B;BX=aXORbADDAX,BXADDAX,BX;AX=2*(aXORb)+aANDbADDAX,A;AX=a+2*(aX

main(){inta,b,c;c=a+b;scanf("%d%d",&a,&b);printf("%d",c);}

#includevoidmain(){intn=1,N,i;scanf("%d",&N);if(N20)printf("shuruwuxiao!\n");else{for(i=1;i

#includeintmain(){inti,s=0;for(i=1;i

m=2a+2b;应该改成m=2*a+2*b;程序中2a,2b是不允许的,没有意义的.