c语言程序判断奇数偶数的程序

你是完全不会写还是不会思路我先写思路吧三条边长度从大到小排列abc比较a平方和b平方+c平方相等直角三角形前面的大钝角三角形后面的大锐角三角形

#include#includevoidmain(){printf("请数输入一个字符：");charch=getchar();if(ch>='a'&&ch='A'&&ch='0'&&ch

#include"stdio.h"voidmain(){inti,j,k,n,a[25];printf("请输入一个数：\n");scanf("%d",&k);if(k/2==(float)k/2)\

main(){intn;printf("pleaseinputanumber\n");scanf("d%",&n);if(n%2==0)printf("thenumberisoushu");elsep

scanf写错了,应写成scanf("%d%d%d",&x,&y,&z);

1#include23intmain(intargc,char*argv[])4{5inta[10],b[10];6inti,j=0,tmp;78for(i=0;i9{10scanf("%d",&a[

#include <stdio.h>void mian(){    int n;   &

scanf("d%",&x);里面的d%应该是%d

1:你要清楚什么样的年份才是闰年（能被4整除且不能被100整除或者能被400整除的,参考http://baike.baidu.com/view/29649.htm）2：判断语句if(((0==year

programExp1(input,output);varn:longint;beginreadln(n);ifodd(n)thenwriteln(1)elsewriteln(2);end.

#include"stdio.h"intmain(){intcountou,countji=0;inti=0;for(i=1;i

longsum_ji(intx)//奇数之和{if（x%2==0）{x--;}return(long)x*(long)x/4;}longsum_ou(intx)//偶数之和{if(x%2!=0){x-

#include <stdio.h>void main(void){ int input[20]; int a=0,b=0;&n

if(x%5==0){g=g+1;sum3=sum3+x;}}}//下面的大括号拿到这里printf("奇数之和为%d\n",sum1);printf("偶数之和为%d\n",sum2);printf

#includeintmain(){intn;while(scanf("%d",&n)!=EOF){if(n%2==0)printf("even\n");elseprintf("odd\n");}re

#includeintmain(intargc,char*argv[]){intm,n;inti;intsum;printf("Pleaseinputmandn:\n");scanf("%d%d",&

#include#defineN3boolrowtest(intn[]){inti,j;intnum;intno_exist=0;for(i=0;i再问：第二组数据测试输入时是个死循环的。。。再答：#

一个表达式就行了：i%2.对2求余,如果结果等于1,则i是奇数,如果结果等于0,则i是偶数.if((i%2)==1){奇数}else{偶数}

#include#includemain(){charbuff[256],*pchar;inta,b,c,i,j;do{if(!gets(buff)){printf("Errorwhengets\n"

voidmain(){intx,i=0,j=0;floats1=0,s2=0,av1,av2;scanf("%d",&x);while(x!=0){if(x%2==0){s1=s1+x;i++}els