c语言程序,输入任意一个数,判断它是否是3或者7的倍数
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/12 18:25:59
#include"stdio.h"intmain(){\x09inti,j,n;\x09inta[12];\x09intmin,mx;\x09scanf("%d",&n);\x09for(i=0;i
intmain(intargc,char*argv[]){intinput;intret,num;printf("Inputaint:");scanf("%d",&input);for(;;){num
很简单,用while#includevoidmain(){intn;intm;printf("输入一个数:");scanf("%d",&n);while(n>=1){m=n%10;
定义四个变量intn,max,min,sum;先读一个数据scanf("%d",&n);sum=max=min=n;再循环9次,输入9个数,同时,累加,比较大小for(i=0;imax)max=n;i
//最近的栈作业~#include<iostream>using namespace std;class Stack{private:int ma
main(){intn;printf("pleaseinputanumber\n");scanf("d%",&n);if(n%2==0)printf("thenumberisoushu");elsep
#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}
swap(int&i,int&j){inttemp;temp=i;i=j;j=temp;}main(){inta,b,cscanf("%d,%d,%d",a,b,c);if(a
运行结果是对的!问题估计错在输入语句的格式上,scanf("%d%d",&a,&b); 两个变量之间没有逗号,那么:从键盘上输入a=1,b=100应该是:
#include <stdio.h> int main (){ int&nbs
可以用sprintf(str,"%d",num);将数字输出为字符串,再用strlen(str)检查其长度:intnulen(intnum){charstr[10];sprintf(str,"%d",
#includeintmain(){inta,b,c,min,max;printf("请输入三个数,用空格键隔开");scanf("%d%d%d",&a,&b,&c);min=ac?b:c);prin
#include#includeintmain(void){intn,sum=0,count=0,s;printf("输入一个整数:");scanf("%d",&n);while(n){s
水仙花数是指一个n位数(n≥3),它的每个位上的数字的n次幂之和等于它本身.(例如:1^3+5^3+3^3=153)注意我这只限于3位数#includevoidmain(){intx,y,z;intn
scanf("%a%b%c",&a,&b,&c);改为,就可以scanf("%lf%lf%lf",&a,&b,&c);
#includevoidmain(){inta;printf("请输入一个三位数:");scanf("%d",&a);printf("各位数上的乘积为:%d\n",(a/100)*(a%10)*(a/
main(){intk;printf("pleaseenter:");scanf("%d",k);printf(“%d”,abs(k));}intabs(inta){returna>0?a:-a;}试
#include <stdio.h>int main(){ int x;//直接选为int型整数 &n
#includemain(){floata,b,s;printf("pleaceinputa,b:\n");scanf("%f%f\n",&a,&b);s=a+b;printf("%f\n",s);/
#include#include#includevoidmain(){inta[100],i,j,t;srand(time(NULL));for(i=0;i