有一分段函数:编写程序,从键盘输入 x,输出 y 的值.
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/16 07:33:49
publiclongpower(intm,intn){if(nreturnm;elsereturnpower(m,n--)*m;}
#include <stdio.h>void main(){int i,j,a,n,k=0,out=0;printf("请输入a与n:")
importjava.util.Scanner;publicclassA{//下面的方法是对单个数求阶乘,并返回publicstaticintjieCheng(intn){intsum=1;for(i
#include#includemain(){floatx,y;scanf("%f",&x);if(x
#include#include#includevoidmain(){inti,n;charstr[10];charcomp[10][6]={"zero","one","two","three","f
请说明白点.比如输入:3423645634524121,你想要输出什么?再问:作业上的题目就是那个我也不知道再答:要求用什么语言编程?汇编?C?……?到底是什么课程的作业?再问:c
F(n)=(1/2)*((sqrt(5)+1)^(n+2)-(1-sqrt(5))^(n+2))/((sqrt(5)+1)^(n+1)-(1-sqrt(5))^(n+1))
;操作说明:;1、输入0~8一位数,显示N!;;2、重复1的过程,Esc键结束程序CodeSegmentAssumeCS:Code,DS:Code;--------------------------
#include#includevoidmain(){doublex;doubley;coutx;if(-2
#include"stdio.h"intmain(){inta1=1,a2=2,n=0,i=1,tmp=a2;doublesum=0.0;printf("输入n:");scanf("%d",&n);w
c语言编写#includevoidmain(){intn,max,min,avg,sum,count=0;max=20;min=20;sum=0;for(n=20;nmax)max=n;if(n
没做输入数据校验.importjava.util.ArrayList;importjava.util.List;importjava.util.Scanner;publicclassAdmin{pub
importjava.util.Scanner;publicclassJiecheng{Scannerin=newScanner(System.in);inta=in.nextInt();int
PrivateSubCommand1_Click()a=Abs(InputBox("请输入第一个整数","输入数据"))b=Abs(InputBox("请输入第二个整数","输入数据"))c=Abs(
input(x)ifx
#includeintmain(){intx,y,a;scanf("%d",&x);scanf("%d",&y);a=x*y;printf("Theaverageis%d\n",a);return0;
如果是要求前N个偶数之和:#includeusingnamespacestd;longFunctionadd(intn){longsum=0;for(inti=0;i
importjava.util.Scanner;publicclassOushu{Oushu(){try{System.out.println("请输入n值");Scannerin=newScanne
PrivateSubCommand1_Click()a=InputBox("请输入数字","提示")b=InputBox("请输入数字","提示")Print"和:"&Val(a)+Val(b)Pri
#include<stdio.h>#include<stdlib.h>intmain(void){inta,b,c=0;charq;while(!c){printf("请输入两