C语言一个正整数,如果它能被7整除,
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#include"stdio.h"intmain(){\x09inti,j,n;\x09inta[12];\x09intmin,mx;\x09scanf("%d",&n);\x09for(i=0;i
#includevoidmain(){inta,sum=0;for(a=1;a
可以编个循环判定一下:(原inta)intb=a;//a原数不能动,所以用b这个数来做循环intc=0;//用来记录判定结果,也可以用bool类型,不过有人说c没有bool,c++才有,所以暂时用in
#include <stdio.h>void main(){ int a,b,c,d,e;  
这个其实可以用多种方法实现方法1:分离数字法varx,l,s:longint;beginread(x);whilex>0dobeginl:=xmod10;inc(s,l);x:=xdiv10;//当前
#includeintmain(){intn;charch;inti;printf("输入一个10以内的正整数和相应个数的五进制成绩:\n");scanf("%d",&n);for(i=0
//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){inti,j,k;for(i=15;i
#include <stdio.h>void main (){ int a[10]; int i,k=0,n,min,
#includeintmat[10][10];voidmain(){intn,i,j;intok=1;scanf("%d",&n);for(i=0;i
#includevoidmain(){intn,m=1,i,j;printf("请输入一个正整数:");scanf("%d",&n);i=n,j=n;while(i>0){m*=i;
#includeintmain(){intnum;inta;//百位intb;//十位intc;//个位scanf("%d",&num);a=num/100;//默认强制转为整型b=(int)(num
#include#includeintmain(intargc,char*argv[]){intnumber,i=1;printf("请输入一个整数:\n");scanf("%d",&number);
#includevoidmain(){\x09inti,n;\x09inta[10];\x09ints,p;\x09printf("n:");\x09scanf("%d",&n);\x09for(i=
#includevoidmain(){inta,b,c,d,e,f,g;printf("请输入两个正整数:");scanf("%d%d",&a,&b);f=a;g=b;if(a
#includeintmain(void){intn=0,m=0,i=0,j=0,k=0;scanf("%d",&n);while(n--){\x09scanf("%d",&m);\x09for(j=
#includevoidmain(){inti,n;printf("pleaseinputn:");scanf("%d",&n);printf("%d=",n);for(i=2;i
楼主这是数学题还是计算机编程?要怎样的回答?能编程解决不#includeusingnamespacestd;intmain(){intcount=0,i,n;for(i=1;i
#includevoidmain(){longintx,ge,shi,bai,qian,wan,bit;scanf("%ld",&x);ge=0;shi=0;bai=0;qian=0;wan=0;bi
#include"stdio.h"#include"math.h"intmain(void){intcount,i,m,n,sum;intrepeat,ri;intprime(intm);scanf(
intn;scanf("%d",&n);if(n%5==0&&n%7==0){printf("YES");}else{printf("NO");}