c语言 输入5*5接的矩阵编程计算

#include<stdio.h>#define ROW 3//行数#define COL 4//列数void PlusMatrix(in

用二维数组,再加上必要的逻辑判断对输入矩阵进行转换即可,最后是每项输出对应一个函数,分布处理.

#includeintmain(){inta[5][5]={{1,2,3,4,5},{1,2,3,4,5},{1,2,3,4,5},{1,2,3,4,5},{1,2,3,4,5}};intsum=0,

#include#include#definen3//三阶矩阵#defineN20#defineerr0.0001voidmain(){inti,j,k;doubleA[n][n],X[n],u,y[

#includeintmain(){inti;voidfun(inta);printf("输入数字：");scanf("%d",&i);fun(i);return0;}voidfun(inta){if

#include#includemain(){floatx,y;while(1){printf("请输入x=");scanf("%f",&x);if(x>=-5&&x

#include"stdio.h"intmain(){     inta[5][5]={0};   

for(i=0;j

if(j==4)\x09\x09\x09\x09printf("%d\n",max);去掉if(j==4)加大括号.改成这样:#defineM3#defineN5#includevoidmain(){

#includeintmain(){floata[5][5],t;inti,j,k;for(i=0;i

涉及到除法,最好用float,不用int.in,out没问题.改正deal_1的下标：voiddeal_1(inta[5][5]){intb[5];inti;for(i=0;i

#include#defineN5voidmain(){\x09intmatrix[N][N];\x09intsum=0;\x09inti,j;\x09printf("请输入一个%d*%d的矩阵：\n

#include#include#includeintmain(void){\x09char*str[5];\x09inti;\x09printf("Inputfivecountries'names:

main()intm[2][3]={1,2,3,4,5,6};for(inti=0;i

#includeintmain(void){inti,j,sum=0;inta[3][3];printf("Inputthearray:\n");for(i=0;i

#includemain(){inta[3][3];inti,j,sum=0;for(i=0;i

#include<stdio.h>int main(){     int n,i,j,k=1;  

#includemain(){chara;printf("inputachar:");scanf("%c",&a);if((a+5)>'z')printf("overflow\n");elseif((

#include"stdio.h"voidmain(){voidzhuan(intarray[2][3],intb[3][2]);intarray[2][3],b[3][2];inti,j;print

switch语句对应离散参数,对此例并不适用,除非你的X限定为了整型,建议用ifelseifelse控制.像那个楼上的,基本上错误一大堆······#includeintmain(void){floa