作业帮csc^2=1 cot^2
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/23 02:16:09
tana+cota+seca+csca=1/(sinacosa)+(cosa+sina)/(sinacosa)=(1+cosa+sina)/(sinacosa)=(1+√2sin(a+45))/(si
sin^2(x)+tan^2(x)+csc^2(x)+sec^2(x)+cos^2(x)+cot^2(x)=31得cos^2(x)+sin^2(x)+tan^2(x)+csc^2(x)+sec^2(x
(tan²a-cot²a)/(sin²a-cos²a)=(sin²a/cos²a-cos²a/sin²a)/(sin&s
楼主几年级啊.不清楚你学没学过那些转换公式.π/2的三角函数值：sin=1cos=0tan不存在sec不存在csc=1cot=1sin165=sin(180-165)=sin15所以是正的cos(16
tanx/(1-cotx)+cotx/(1-tanx)=tanx/(1-cosx/sinx)+cotx/(1-sinx/cosx)=sinxtanx/(sinx-cosx)+cosxcotx/(cos
1+tan^2α=1+(sinα/cosα)^2=(cos^2α+sin^2α)/cos^2α=1/cos^2α=sec^2α第二个类似
大致能看清楚吧,就是把原式转化成e^xsinydx+(e^xcosy+2y)dy=o这个全微分方程,然后用全微分方程的方法做,答案是e^xsiny+y^2=C
tanθ+cotθ=3(tanθ+cotθ)^=tan^2θ+2+cot^2θ=9tan^2θ+2+cot^2θ=7secθcscθ=1/(sinθcosθ)=sin^2θcos^2θ/sinθcos
左边=(sin²x/cos²x-cos²x/sin²x)/(sin²x-cos²x)=[(sin^4x-cos^4x)/cos²x
(tan²a-cot²a)/(sin²a-cos²a)=(sin²a/cos²a-cos²a/sin²a)/(sin&#
sin^2x+cos^2x=1所以左边=tan^2x-cot^2x=sin^2x/cos^2x-cos^2x/sin^2x=(sin^4x-cos^4x)/sin^2xcos^2x=(sin^2x+c
seca
cot是余切cot=cos/sinsec叫正割,sec=1/coscsc叫余割,csc=1/sin
这是两个三角公式.sec²x=1/cos²x=(sin²x+cos²x)/cos²x=tan²x+1csc²x=1/sin
可以构造一个直角三角形,其中C=90度设cotx=BC/AC=1/2,则：AB=根号5因为：0
(tg^2a-ctg^2a)/(sin^2a-cos^2a)=(sin^2a/cos^2a-cos^2a/sin^2a)/(sin^2a-cos^2a)=(sin^4a-cos^4a/sin^2a*c
都化成sin、cos形式（我用s表示sinα,c表示cosα）且s^2+c^2=1(s/c)^2+(c/s)^2+(1/c)^2+(1/s)^2=(1+s^2)/c^2+(1+c^2)/s^2通分有（
1.y=(tan^2x-csc^2x)/(tan^2x+cot^2x-1)=(sin^2x/cos^2x-1/sin^2x)/(sin^2x/cos^2x+cos^2x/sin^2x-1)=(sin^