作业帮cosxπ4等于
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/26 13:42:39
设t=π/2-xsinxdx/(sinx+cosx)=-cosdt/(sint+cost)sinxdx/(sinx+cosx)从0积到π/2等于-cosdt/(sint+cost)从π/2积到0等于c
cos2X=(cosX)^2-(sinX)^2=2*(cosX)^2-1
sin(x-3π/4)=sin[π-(π/4-x)]=sin(π/4-x)=-sin(x-π/4)sin(x-3π/4)cos(x-π/4)=-sin(x-π/4)cos(x-π/4)=-sin(2x
y=4sin的平方x+4cosx+5=4(1-cos的平方x)+4cosx+5=-4cos的平方x+4cosx+9=-4(cosx-1/2)^2+10-π/3小于等于x小于等于（2π）/3-1/2≤c
sin^2x+cos^2x=1(sinx+cosx)^2=1+2sinxcosx=1+sin2x=1-24/25=1/25sinx+cosx=1/25或sinx+cosx=-1/25又,x属于(-π/
f（x）=sinx/4+cosx/4=√2[sin(x/4)（√2）/2+cos(x/4)(√2)/2]=√2[sin(x/4)cos(π/4)+cos(x/4)sin(π/4)]=√2sin(x/4
secx-1=(1/cosx)-1=(1/cosx)-(cosx/cosx)=(1-cosx)/cosx
设x=sinxf（-x）+3f（x）=4*x*√(1-x^2).①设x--sinxf（x）+3f（-x）=4*（-x）*√(1-x^2).②①②分别相加相减得到③④4f（x）+4f（-x）=0.③2f
原式=sin(x-π/4）/cos（x-π/4）=（sinxcosπ/4-cosxsinπ/4）/（cosxcosπ/4+sinxsinπ/4）=【√2/2（sinx-cosx）】/【√2/2（sin
两种情况sinx=3/5cosx=-4/5或者sinx=-3/5cosx=4/5再问：лл
cos(x)=1/√2√[cos(x)]=√(1/√2)=1/[2^(1/4)]=2^(-1/4)=1.1892
x∈(-π,0),且cosx=-3/4所以x∈(-π,-π/2)x=π+arccos(3/4)再问：不是arccos(-3/4）吗那个负号呢再答：x∈(-π,-π/2)所以x是第三象限角而x=arcc
tan(2013π+x)=cosxtanx=cosxsinx/cosx=cosxsinx=cos²x=1-sin²x则sin²x+sinx-1=0因为-1
等于+-根号下(1+cos)/2
x=(3π/2,2π)sinx
倍角公式逆用：cos2x=cos²x-sin²x=2cos²x-1=1-2sin²x1-2cos²x/4=-(2cos²x/4-1)=-co
[2π/3+2kπ,4π/3+2kπ]k为Z.
1-COSX不恒等于SINX1-(COSX)^2等于(SINX)^2
f(x)=(sinx)^2+cosx=1-(cosx)^2+cosx=-(cosx)^2+cosx+1设t=cosx|x|≤π/4√2/2≤t≤1y=-t^2+t+1=-(t-1/2)^2+5/4在[