数学,先化简再求值(x分之x 2
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/09 14:14:33
题目有误吧(x-x)x-1分之4(x-x)+(x-2)再问:(x方-x)(x-2)方再答:
是(x^2/(x-1)-x+1)/(4x^2/(1-x)-4x+1)吗原式=(x-x+1)(x+x-1)/(x-1)/((4x^2-4x+1+4x^2-x)/(1-x))=-(2x-1)/(4x^2-
解:原式=(x-y)×(xy)分之(xy)的平方-(x-y)的平方乘以(x的平方×y的平方)分之(y的平方-x的平方)=-(xy分之4)当x=2根号3,y=2-根号3时;代入-(xy分之4),结果为5
2x²+(﹣x²+3xy+2y²)-(﹣x²-xy+2y²)=2x²-x²+3xy+2y²+x²+xy-2y&
小括号内先通分:分母为x平方-4,分子为3x平方+6x,另一个是x平方-2x化简:{x²-4分之2x²+8x}÷x²-4分之2x结果=x+4
【先化简再求值】(x-1)分之x÷【(1-x分之1)-1-x】=(x-1)分之x÷(x^2/(1-x))=-1/xx=1时,原式无意义,x=2时,原式=-1/2,x=0时,原式无意义【选择题】下列约分
————请采纳,亲.*^_^*如果对答案不满意,可以继续追问哦!再答:
原式=y(x+2y)(x-2y)/(x+2y)²*(4xy+x²-2xy)/(x-2y)=y(x-2y)/(x+2y)*(x²+2xy)/(x-2y)=y(x-2y)/(
x²+2x+1=10(x+1)²=10x+1=3或x+1=-3所以x=2或x=-4【(x²+4)/x-4】÷【(x²-4)/(x²+2x)】=【(x&
原式=(x-1)(x+1)/(x+2)*(x+2)/x-1=x+1然后代入数值即可很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,
(x^2-2x+1)/(x^2-1)+1/(x+1)=(x-1)^2/(x+1)(x-1)+1/(x+1)=(x-1)/(x+1)+1/(x+1)=x/(x+1)=1-根2分之一
=(x-2)×2x/(x+2)(x-2)+4/(x+2)=2x/(x+2)+4/(x+2)=(2x+4)/(x+2)=22、(x-1-1)/(x-1)×(x-1)²/(x+2)(x-2)=(
x²-3x+2=0(x-1)(x-2)=0因为分母x-1≠0所以x-2=0x=2原式=x(x-1)/(x-1)*(x+1)(x-1)/(x-1)²=x*(x+1)/(x-1)=2*
原式=[2x(x+2)-x(x-2)]/(x²-4)+x/(x²-4)=(x²+7x)/(x²-4)=[x(x+7)]/[(x+2)(x-2)]代入x=5原式=
{1-x/(x-1)}÷1/x(x-1)=(x-1-x)/(x-1)÷1/x(x-1)=-1/(x-1)÷1/x(x-1)=-x
[(x-4)/(x^2-1)]÷[(x^2-3x-4)/(x^2+2x+1)]+1/(x-1)=[(x-4)/(x-1)(x+1)]÷[(x+1)(x-4)/(x+1)^2]+1/(x-1)=[(x-
原式=(x+1)/(x+1)²×x(x-1)/[-2(x-1)]=-1/(x+1)×x/2=-x/2(x+1)当x=√2时原式=-√2/2(√2+1)=-√2(√2-1)/2=(√2-2)/
(x-2-x+2分之5)÷2x+4分之x-3=(x-2-x+5/2)÷2x+x/4-3=1/2÷2x+x/4-3=1/4x+x/4-3