C 计算1 100之间的所有3和7的倍数之和-搜答案-智慧作业帮

#includeintmain(intargc,char*argv[]){inti,a,b,sum=0,c;scanf("%d%d",&a,&b);if(a>b){c=a;a=b;b=a;}for(i

#includevoidmain(){\x09inti,s=0;\x09for(i=800;i

第一个是正确的我来解释doublefun(intn){intm,k,i;doubles=0.0;for(m=3;m

Sum=0Fori=100To300IfiMod21=0ThenSum=Sum+iEndIfNext==>优化一点：Sum=0Fori=100To300IfiMod21=0ThenSum=Sum+ii

#includeintmain(void){inti,sum;sum=0;for(i=1;i

//先求3到100间的所有素数,存在数组中；//求该数组的所有为素数的元素之和,然后开方求平方根#include#includeintsushu[98];//开辟个最大容量的,假设都是素数/*从2开始

//---------------------------------------------------------------------------#includeintmain(void){i

#include<stdio.h>main(){ int i=0,sum=0; &nb

eturn(a+b)*(b-a+1)/2

main(){inti,n,sum=0;printf("%d",&n)for(i=1;i

1+3+...+99=(1+99)*50/2=2500

publicclassSumOfEven{\x09publicstaticvoidmain(String[]args){\x09\x09intsum=0;\x09\x09for(inti=1;i

#includevoidmain(){inti;intsum=0;for(i=1;i

#includeintmain(intargc,char*argv[]){intm,n;inti;intsum;printf("Pleaseinputmandn:\n");scanf("%d%d",&

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e&

subbeisu()dimbeisu3asintegerdimbeixu7asintegerbeisu3=0beisu7=0fori=1to1000ifimod3=0thenbeisu3=beisu3

//分别计算1到1000之间所有3的倍数之和和所有7的倍数之和intmain(){intsumA=0;//3的倍数的和intsumB=0;//7的倍数的和for(inti=1;i

n=3s=0dowhilen

intfoo(){//只可能有奇inti=(7*13*5);//455intsum=0;while(i

楼上推荐的程序有个问题.3*7*9应该写成7*9,否则会漏掉63dimiasintegerdimjasintegerdimSasLongS=0fori=1to13230ifimodj=0thenS=S