c 编程实现 求鸡和兔的个数 已知头数腿数

#include#includeintmain(void){inti,count=0;floattotal=0;charct[10];printf("4digitreturn:\n");for(i=1

8086汇编：设数据存在内存BUF开始的单元中,长度为N,奇数的个数存在ALMOVCX,NMOVAL,0LEADI,BUFL1:TEST[DI],01HJZNEXTINCALNEXT:INCDILOO

publicclassa{publicstaticvoidmain(Strings[]){intsum=0,count=0;for(inti=100;i0)continue;sum+=i;count+

#include//函数,读数操作数intgetNextNum(){intret;scanf("%d",&ret);returnret;}//函数,读运算符chargetOpt(){returnget

#include"stdio.h"intmain(){intn,x;doublesum=0;intmax=0;doubleavg;intmin=1再问：不能运行这个程序，有错误再答：#include"

在另一个帖子回答了

#includeintmain(){\x09inti,sum=0;\x09for(i=1;i

#include"stdio.h"voidmain(){longa=1,n,s=0;for(n=1;n

#include#includemain(){doublearea,length;doubler=pi=3.1215926area=pi*r*r；length=2*pi*r；}

dimiasinteger,nasinteger,sasinteger,kasintegerfori=1to10k=val(inputbox("请输入一个整数："))ifkmod2=1thenn=n+

#includemain(){inti,n=0,sum=0;inta[10];printf("n\输入10个数:");for(i=0;i

intmain(){inttemp;/*用于临时保存输入的整数*/intsum=0;/*用于求和*/intcount=0;inti;/*输入这10个数*/for(i=0;i{scanf("%d",&t

#includeintmain(){inti,n,sum=0,flag=0;printf("请输入n:");scanf("%d",&n);for(i=1;i=100&&flag==0){printf(

#includeintmain(){inta,b,c,average;printf("a=");scanf("%d",&a);printf("b=");scanf("%d",&b);printf("c

#include<stdio.h>#define Pi 3.14159double Square(double r){  &nb

main(){intp,r,n,m,temp;printf("Pleaseenter2numbersn,m:");scanf("%d,%d",&n,&m);//输入两个正整数.if(n

#include"stdio.h"voidmain(){voidzhuan(intarray[2][3],intb[3][2]);intarray[2][3],b[3][2];inti,j;print

main(){inttemp[30];intsum,i;temp[0]=3;temp[1]=4;temp[2]=5;for(i=3;i

#includemain(void){\x05inti,s;\x05\x05for(i=1,s=0;;i++)\x05{\x05\x05s+=i;\x05\x05if(s>=100)\x05\x05{

#includemain(){intx=0,y=0,point=0;//x苹果的个数,y梨的个数for(x=1;x{for(y=1;y{if(x*0.5+y*0.8>100)//满足条件{if((x-