c 怎么保存小数点后500位

这是1000000位3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348

这个问题还是蛮简单的：#include <stdio.h>#define N 100int main(){   &nb

用Mathematica或SuperPi算.Mathematica输入N[Pi,1000000000],按回车得出结果.

圆周率500位3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253

314000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

哥们,你这程序有问题x是double型的,在输入数据的时候是不允许使用“%f”的,double型的数据输入必须使用“%lf”还有,“scanf("%15.10f",&x);”15.10这个是不允许出现

右键-单元格格式--数值--小数点后保留两位

3.14159265358979323846264338327950288419716939937510582097494459230781640628620899862803482534211706

#includeintmain(){intn1,n2,i;printf("pleaseinputtwonumbers:");scanf("%d%d",&n1,&n2);printf("n1/n

3.14159265358979323846264338327950288419716939937510582097494459230781640628620899862803482534211706

怎样快速记忆圆周率小数点后200位?有话在先:使用人的想象力记忆东西是一件令人愉快的事,下面是圆周率后200位的记忆方法(这是我自己的想出的内容,每个人的想象力不一样,所以想的不一定一样,但原理是一样

3.1415926535897932384626433　　83279502884197169399

我知道：圆周率3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253

圆周率2500位圆周率500位3.14159265358979323846264338327950288419716939937510582097494459230781640628620899862

3.14159265358979323846264338327950288419716939937510582097494459230781640628620899862803482534211706

问题补充：π小数点后100位圆周率500位3.14159265358979323846264338327950288419716939937510582097494459230781640628620

3.14159265358979323846264338327950288419716939937510582097494459230781640628620899862803482534211706

下面的小故事利用谐音记住∏的小数点后100位数字.先设想一个酒徒在山寺狂饮,醉死山沟的情景：山巅一寺一壶酒（3.14159）,儿乐（26）,我三壶不够吃（535897）,酒杀尔（932）!杀不死（38

975-1000位：9278766111959092164201989圆周率1000位是9

选定,右键-设置单元格格式-数值-小数位数-2