C 如何输入任意N个数

#includevoidmain(){inti,n,arr[100],mul=1;printf("请输入n值：");scanf("%d",&n);for(i=0;i

//#includevoidmain(){intm,n,i,min,max;printf("Pleaseinputm,n:\n");scanf("%d%d",&m,&n);min=mn?m:n;if(

#includevoidsx(intx[],intn){inti,j,t;for(i=0;i

#include <stdio.h>;int main(int argc, char **argv) {  

楼主看这里#includevoidmain（）{inti,j,num=0;for(i=0;i

#include#includeintmain(){intnumber[10];//存输入的十个数floatodd=0.0;//奇数平均值floateven=0.0;//偶数平均值intji=0;//

#includeintmain(){inta[10];inti,j;intt,sum=0;for(i=0;i{scanf("%d",&a[i]);sum+=a[i];}for(j=0;jfor(i=0

#include <stdio.h>#include <stdlib.h>int main(){  int i,&n

#include#defineN100intmain(){inta[N],i,j,count1,count2;floatave1,ave2;count1=count2=ave1=ave2=0;for(

voidmain(){inta[100],b,max,min,i,sun=0;floatping=0;printf("Pleaseenterthenumberrequiredtoenternumber

#includeintStrchr(chars[],charch){intl,i;intj=0;l=strlen(s);for(i=0;i

#includevoidmain(){inti,n,m,jh=0,oh=0,jg=0,og=0;printf("请输入n的值:\n");scanf("%d",&n);//先输入数据个数nprintf(

1.编译不通过数组定义时,不能使用变量,即使变量已赋值,所以inta[n]；是错的解决方法,你可以直接定义一个大的数组,比如inta[100],然后再用n限制输入的个数2.数组下标是从0~n-1,所以

publicclassTestNum{publicstaticvoidmain(String[]args){Scannersca=newScanner(System.in);intnum=0;ints

#include#defineN20//默认数组大小20intmain(){inta[N],i;doubleave=0;printf("输入20个数\n");for(i=0;i

#includevoidmain(){intn,m[20],i,j=0;intA=0,B=0,C;scanf("%d\n",&n);for(i=0;i

方法很多,以下是按照各边的次序填充再输出：#include<stdio.h>intmain(){inti,j,a[100][100],n,k=1;printf("pleaseinputan

#include"iostream.h"voidmain(){inti,n;coutn;intadd=0;for(i=0;i

#include#include#defineMAX1000intmain(){inta[MAX],i,j,n,p,q,s1,s2;p=0;q=0;s1=0;s2=0;printf("请输入要输入的值

#includevoidmain(){intn,i,ji=0,ou=0;//ji用来统计奇数的个数,ou用来统计偶数的个数intinput,jihe=0,ouhe=0;//jihe用来统计奇数的和,o