c 修改程序使其可以计算s=1! 2! 3! ... n!
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/19 00:11:34
#include"stdio.h"voidfun(intn,intk){intj;doublesum=0;for(j=1;j
没得错误,main函数前面加void就好了
s=0k=1whilei
#include#includevoidmain(){floats=0;inti;floatt=1;for(i=1;;i=i+2){if(fabs(t/i)
子程序f(intx){floatm;ifx>0{ifx=1m=1;elsem=x*f(x-1);}elsem=0;}主程序输入a,b,c;读取a,b,c;调用函数s=f(a)+f(b)+f(c)
#includeintmain(void){intn;inti,j;floatsum=1.0;floatdex=1.0;printf("输入一个数:");scanf("%d",&n);for(i=2;
#includeintmain(void){intn=0,i=0;doublep=1,q=0,s=0;printf("n=");scanf("%d",&n);for(i=1;i
PrivateSubCommand1_Click()DimiAsDoubleDimnAsDoubleDimsumAsDoublesum=0IfNotIsNumeric(Text1.Text)Then'
eturn(a+b)*(b-a+1)/2
#includeintmain(){doublea;charfh='+';doublesum=0.0;while(scanf("%lf",&a)!=EOF){if(fh=='+')sum+=a;els
#includevoidmain(){intn,t=1,s=0;for(n=1;n
#includeintmain(void){inti=1,s=0;while(i
publicclassTest{publicstaticvoidmain(String[]args){ints=0;intn=1;for(inti=0;i
#include <stdio.h>void main(){ int n;//n没声明int i=1,sum;sum=0;//sum没初始
最简单的程序,vc6通过调试运行#includevoidmain(){intn,i,s=0;scanf("%d",&n);for(i=1;i
;MOVAX,AANDAX,B;AX=aANDbMOVBX,AXORBX,B;BX=aXORbADDAX,BXADDAX,BX;AX=2*(aXORb)+aANDbADDAX,A;AX=a+2*(aX
CLEARSETTALKOffs1=0forn=1to10s1=s1+jc(n)next"1!+2!+3!+.+10!=",s1FUNCTIONjcPARAMETERSis=1FORj=1TOis=s
=(1/2)*底*高s=(1/2)*a*b*sinC(C为a,b的夹角)底*高/2底X高除2二分之一的(两边的长度X夹角的正弦)s=1/2的周长*内切圆半径s=(1/2)*底*高s=(1/2)*a*b
我给你一个思路,你自己去编一下,实在不行再问!程序为实数集,设一个变量,用来存放正数之和;设一个变量,用来存放负数之和;设一个变量,用来存放要计算的数,还要一个指钍变量,用来计数输入的数组;程序执行过
#includeintmain(){inti,s=0;for(i=1;i