an−13an bn 12bn=_____.

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Tom is _(a/an)European boy

a因为E发U再问:u��Ҳ��Ԫ����再答:发音/ju:/再问:лл再答:先是原辅音/y/再答:/j/再答:不好意思发错了

Shakeapeare was _ a writer _ an actor.He

莎士比亚是主语,只有一个人,bothand用于两者,所以选A

英语翻译1、an interesting place to go or thing to do_ _ _ _ _ _ _

还挺难,1.attraction景点2.interview面试3.underground地下4.amusement游乐场5.footprint脚印6.character角色7.mail邮件8.coas

We should take part in meeting actively.=We should _ _ _ _ _

1,takeanactivepart2,weighed,startedleaving

1.Simon finds reading is very interesting.=Simon _ _ _ _ _.

SimonisveryinterestedinreadingTheboyistheclevereststudentamongthestudentsYoudon'tneedtogettherebefor

数列{an}满足a1=33,a(n+1)-an=2n,则an/n的最小值为_

a1=33,a(n)-a(n-1)=2(n-1),a(n)=a1+(a2-a1)+(a3-a2)+……+(a(n)-a(n-1))=33+2+2×2+……+2(n-1)=33+n(n-1).an/n=

已知正整数数列{an}中,a1小于等于a2,anan+1=2,则数列{an}的一个通项公式为_.

我理解的你的题目,是要求第N项与第N+1项之积等于2下面这个数列显然符合你的题目要求:1,2,1,2,1,2,1……其通项公式为an=(3+(-1)^n)/2

3500"=_°_'_"

=_58.3'=_0.97°

若数列{an} 中,a1=1,a2=3+5,a3=7+9+11,a4=13+15+17+19,…,则a10=_

观察数列{an} 中,a1=1,a2=3+5,a3=7+9+11,a4=13+15+17+19,…,各组和式的第一个数为:1,3,7,13,…即1,1+2,1+2+2×2,1+2+2×2+2

已知数列{an}中a1=1,a2=3,an=3an-1_-2an-2.求数列an的通项公式

这道题不难,不必用数学归纳法做,下面给出几种算法.an=3an-1+2an-2可以做以下变形①(an-an-1)=2(an-1-an-2)②(an-2an-1)=an-1-2an-2(辅助思考:用特征

He decided to teach himself French=He _ _ _ _ to _ French _

HedecidedtoteachhimselfFrench=He【made】【up】【his】【mind】to【learn】French【by】【himself】.Shewantedtoknowwhe

_ _ food _ animals.=_ _ _ food at animals.〔throw〕

Don'tthrowfoodatanimals.Youshouldn'tthrowfoodatanimals.

He got an idea.=He came _ _an idea.

up,再问:亲,两个空再问:还有Wheredidyougo?=Where?you?再答:cameupwith

已知{an}等差数列,a1=1 ,S10=100,an=_,令an=㏒2bn则前5项之和S5=_

S10=(a1+a10)*10/2=100所以a10=19所以d=(a10-a1)/(10-1)=2所以an=a1+(n-1)d=2n-1所以bn=2^(2n-1)那么S5=b1+...+b5=2^1

若极限lim((3n^2+4)/(n+2)-an+b)=6,则a=_,b=_

=lim[3n^2+4-(n+2)an+(n+2)b]/(n+2)=lim[(3-a)n^2+(b-2a)n+2b+4]/(n+2)n趋向无穷大时,因为其极限存在,所以n的二次项系数必为0,所以3-a