当(3m n)(m 3n-1)=72时,求m n的最小值
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整数的加减:1/4MN-1/3MN+7=-1/12MN+7
当m=-3,n=1/2时m^2n+[2mn^2-(3m^2n-2mn^2)]=m^2n+2mn^2-3m^2n+2mn^2=-2m^2n+4mn^2=-2mn(m-2n)=-2x(-3)x1/2x(-
(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)先去括号=2mn+2m+3n-3mn-2n+2m-m-4n-mn合并同类项=-2mn+3m-3n=-2mn+3(m-n)把m-n=2,
-3kmn-(1/3)mn=0k=-1/9
(m+n)平方-3mn=3²-3×1=9-3=6
已知﹣3xy的n+1次方与5x的m+3y四次方是同类项则1=m+3n+1=4解得m=-2n=3所以3n四次方-6m3n-4n四次方+2nm3次方=-n^4-4m^3n=-3^4-4*(-2)^3*3=
先合并同类项,得3(m-n)-6mn+9,代入已知数据,有结果27
原式=mn(m2-9)=mn(m+3)(m-3).故答案为:mn(m+3)(m-3)
-(mn-3)+3(-mn-1)-5mn=-mn+3-3mn-3-5mn=-9mn=-9*2*23=-414
当x=0时,mn=3,当x=1时,a+b+mn=2,所以a+b=-1,所以2a+2b+3mn=-2+3×3=7.∵a+b=-1,∴a²+b²+2ab=1,所以a²+b
(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)=-2mn+2m+3n-3mn-2n+2m-m-4n-mn=(-2mn-3mn-mn)+(2m+2m-m)+(3n-2n-4n)=-
64=MQ=1/2MP=1/2*4/3MNSOMN=4*2/1*3/4=6
原式=m²-[(9k+1)/3]mn-3n²-6∵不含mn项∴mn项的系数(9k+1)/3=0故k=-1/9
-5m²n+(2mn²+5m²n)-2(3m²-mn²)=-5m²n+2mn²+5m²n-6m²+2mn
-2mn+2m+3n-3mn-2n+2m-4n-m-mn=-6mn+3m-3n=-6mn+3(m-n)=6+9=15
-2(mn-3m平方)-{m平方-5(mn-m平方)+2mn},其中m=1,n=-2=-2mn+6m^2-m^2+5(mn-m^2)-2mn=-2mn+6m^2-m^2+5mn-5m^2-2mn=mn
-2(mn-3m的2次方)-【m的2次方-5(mn-m的2次方)+2mn】=-2mn+6m²-m²+5mn-5m²-2mn=mn当m=1,n=-2时原式=mn=1×(-2
1、标准立方米每小时.由于气体体积随温度、压强变化而变化,所以必须规定一个标准的温度和压强,才能有可比性地测量气体的体积.2、兆焦每吨.3、质量百分率.如果是%(V/V),则是体积百分率.4、不知道.
已知mn=-1,m-n=4则(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)=-2mn+m+n-3mn-5n+5m-m-4n+3mn=-2mn+5m-8n=2+20-3n=22-3n
绝对值m-1+(n+2)²=0m-1=0m=1n+2=0n=-2-2(mn-3m²)-[m²-5(mn-m²)+2mn].=-2mn+6m²-m