a=log3πb=log2根号3,c=log3根号2-搜答案-智慧作业帮

log2(a)=log3(b)=log5(c)

log23=a;log37=b即lg3/lg2=a;lg7/lg3=b;所以lg7/lg2=a*b所以log72=1/a*b同理log142=1/1+ab;所以结果为（3+ab）/(1+ab)

c=log2(0.8)1b=0.6^5b>c

运用换底:log14(56)=log3(56)/log3(14)=〔log3(7)＋log3(8)〕/〔log3(7)＋log3(2)〕log3(2)=1/log2(3)=1/alog3(8)=3lo

答：ab=log2^7ab+1=log2^7+1=log2^14ab+3=log2^7+3=log2^56log14^56=(ab+3)/(ab+1)

log14^56=log3^56/log3^14=(log3^7+3log3^2)/(log3^7+log3^2)=(b+3/a)/(b+1/a)=(3+ab)/(1+a)

若log23=a,log37=b则log23*log37=ab即log27=ablog1456=log214/(log256)=(log22*7)/(log27*8)=(log22+log27)/(l

log3为增函数所以可以比较真数大小π>根2所以a>clog2根3=x所以2^x=根3log3根2=y所以3^y=根2明显是x>y所以a>b>c

题目错了

log2(log0.5(log2a))=0log0.5(log2a)=1log2a=0.5a=平方根下2,log3(log1/3(log3b))=0log1/3(log3b)=1log3b=1/3b=

点击图片就可以看清楚了,加油!

a>log3(3)=1,a>10=log2(1)b>c

运用换底:log14(56)=log3(56)/log3(14)=〔log3(7)＋log3(8)〕/〔log3(7)＋log3(2)〕log3(2)=1/log2(3)=1/alog3(8)=3lo

log1256=lg56/lg12=(3lg2+lg7)/(lg3+lg4)因为a=lg3/lg2所以lg3=alg2因为b=lg7/lg3所以lg7=blg3=ablg2所以原式=(3lg2+abl

a=lg3/lg2b=lg7/lg3log4256=lg56/lg42=(lg7+3lg2)/(lg2+lg3+lg7)=(lg7/lg3+3lg2/lg3)/(lg2/lg3+1+lg7/lg3)=

已知log210=a,换底公式1/lg2=alg2=1/alog310=b1/lg3=blg3=1/blog3(4)=lg4/lg3=2lg2/lg3=2b/a请参考……

log3(2)=lg2/lg3=a/blog3(4)=2log3(2)=2a/

你好a=log[2]3√3＞1b=log[2]（9/√3）=log[2]3√3=ac=log[3]2＜1所以c＜b=a很高兴为您解答,祝你学习进步!有不明白的可以追问!如果有其他问题请另发或点击向我求

1/log3(4)1/2*(log2(2))=1/2c=1/2*(log3(2))c

=log2√3,c=log3√22^b=√33^c=√2比较得b>c