已知方程组2x 3y=52Y 3X=10
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/22 13:55:11
∵|2x-3y+1|+(x+3y+5)的二次方=0∴2x-3y+1=0x+3y+5=0x=-2y=-1∴(-2x*y)的二次方(-y的二次方)×6xy平方的值=4x⁴y*(-y²
3y^2=12y3y^2-12y=03y(y-4)=0y1=0,y2=43x^2-5x=0x(3x-5)=0x1=0,x2=5/3(x+3)^2=2x(x+3)x^2+6x+9=2x^2+6xx^2=
x2y+xy2=xy(x+y)=66,设xy=m,x+y=n,由xy+x+y=17,得到m+n=17,由xy(x+y)=66,得到mn=66,∴m=6,n=11或m=11,n=6(舍去),∴xy=m=
x3y+2x2y2+xy3=xy(x2+2xy+y2)=xy(x+y)2,∵x+y=5,∴(x+y)2=25,x2+y2+2xy=25,∵x2+y2=13,∴xy=6,∴xy(x+y)2=6×25=1
原式=(x4-xy3)+(y4-x3y)+(3xy2-3x2y)=x(x3-y3)+y(y3-x3)+3xy(y-x)=(x3-y3)(x-y)-3xy(x-y)=(x-y)(x3-y3-3xy)=(
解方程组2x−5=y,①3x−2y=12,②时,把①代入②即可消去y,达到消元的目的;解方程组2x+3y=133x−4y=−6时,想法把y的系数化为相同,然后用减法化去,达到消元的目的.故答案是:代入
原式=4x29y2•27y364x3•4xy=34x2.故答案为34x2.
∵x+y=4,∴(x+y)2=16,∴x2+y2+2xy=16,而x2+y2=14,∴xy=1,∴x3y-2x2y2+xy3=xy(x2-2xy+y2)=14-2=12.
y的平方+4=6Y公式B平方-4乘A乘CA=1B=-6C=4《A为2次项系数.》即:36-16=20Y=《-B+-根号B平方-4乘A乘C》除以2A最后Y=3+2倍根号5和3—2倍根号5
(2x4-4x3y-x2y2)-2(x4-2x3y-y3)+x2y2=2x4-4x3y-x2y2-2x4+4x3y+2y3+x2y2=2y3,因为化简的结果中不含x,所以原式的值与x值无关.
1.15-9y-9x>-9/43.3(x-1)-x+1212x>32X>8/3
已知x+y=5,xy=3,代数式x3y-2x平方y平方+xy3=xy(x²-2xy+y²)=xy(x-y)²=3×[(x+y)²-4xy]=3×(25-12)=
∵|x+y+1|≥0,|xy-3|≥0|x+y+1|+|xy-3|=0,∴x+y+1=0,即x+y=-1xy=3xy3+x3y=xy(x²+y²)=yx[(x+y)²-2
x+y=4,xy=2后者平方后二式相加再加后者平方
x3y+xy3=xy(x^2+y^2)=(√3-√2)(√3+√2)((√3-√2)^2)+(√3-√2)^2)=1*(3-2√6+2+3+2√6+2)=10
(x-y)2=x2-2xy+y2=9,当x2+y2=13时,13-2xy=9,解得xy=2.当xy=2,x2+y2=13时,x3y-8x2y2+xy3=xy(x2-8xy+y2)=2×(13-8×2)
∵x+y=3,∴(x+y)2=9,即x2+y2+2xy=9①,又x2+y2-3xy=4②,①-②,得5xy=5,xy=1.∴x2+y2=4+3xy=7.∴x3y+xy3=xy(x2+y2)=7.故答案
∵x-y=l,xy=2,∴x3y-2x2y2+xy3=xy(x2-2xy+y2)=xy(x-y)2=2×1=2.
a1=a2,b1=-b2,c1=c2a1=a2,b1=b2,c1不等于c2a1不等于a2,b1不等于b2,c1不等于c2
2x+3y=-k+2,①3x-2y=5k+3②2*①+3*②13x=13k+13所以x=k+1代入①y=-kx-y=2k+1=5k=2