已知多项式A=2x²-4xy-5y B=2x² 2xy 2y²
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/21 23:26:19
∵A=3X²Y-4XY²,B=-X²Y-2XY²A+2B+C=0∴C=-A-2B=-(3x²y-4xy²)+2(x²y+2xy
多项式3x的2a-1次方y的平方-1/2x的立方y+xy/4是五次多项式,所以2a-1+2=52a=4a=2
=-x-(2y-2+3x)+2(x+4)=-x-2y+2-3x+2x+8=-4x-2y+10
C=-(A+B)=-(2x^2+3xy-2x+(-)x^2+xy-1)=-x^2-4xy+2x+2x^2表示x的平方
A=3x^2y-4xy^2B=-x^2y-2xy^2A+B=3x^2y-4xy^2-x^2y-2xy^2=2x^2y-6xy^2A+B+C=0C=-(A+B)=-(2x^2y-6xy^2)=6xy^2
(x+y)²=4x²+2xy+y²=4x²+y²-6=4x²+y²=101/2(x²+y²)-xy=1/2x1
已知x+y=3xy=2那么-x²y-xy²=-xy(x+y)=-2*3=-6如果不懂,祝学习愉快!
A=(12xy-10xy²-2xy²)÷(-4xy)=(-12xy²-12xy)÷(-4xy)=3y+3即多项式A=3y+3
a-1=0a=12b+2=0b=-13a+5b=-2再问:确定对吗?如果明天作业交上去改了后,对的话我再给满意回答。
再问:-ab(a-b)²+a(b-a)²-ac(a-b)²再答:
解2(x+3y-2xy)-(4x+8y-2xy)=2x+6y-4xy-4x-8y+8xy=-2x-2y+4xy=-2(x+y)+4xy=-2×5+4×3=12-10=24x²-3y²
3|x+1|+2(y-1)^2=0x+1=0y-1=0x=-1y=1(x^2+4xy-2y^2)-(x^2+y)-2(y^2+xy)-1/2(x-8y^2)=x^2+4xy-2y^2-x^2-y-2y
x+y=-5,xy=63xy^2+3x^2y=3xy(y+x)=3×6×(-5)=-90
(1)-xy²+2x²y+3x³-4y³=3x³+2x²y-xy²-4y³(2)-xy²+2x²y+
M=(2x^2y+xy^2)(x-2y)-(2x^2-3xy+xy^2)(-xy)很简单啊.
因为不含二次方程,所以二次项系数为零a-2=0,2b+1=0所以a=2,b=-0.53a+8b=2
你的题目好像有误,哪一项里有b阿
3A+B-[B-½(2A+4B)]=3A+B-(B-A-2B)=3A+B-B+A+2B=4A+2B=4(x³-2xy²+1)+2(x³+xy²-3x&
多项式X^2+(2a+4)xy+y^2-1不含xy项,即xy项前的系数为0所以2a+4=0,a=-2
(2x+3y-2xy)-(x+4y+xy)-(3xy+2y-2x)=2x+3y-2xy-x-4y-xy-3xy-2y+2x=(2x-x+2x)+(3y-4y-2y)-(2xy+xy+3xy)=3x-3