已知分式方程X-4 X=2 X-4 a无解,求a的值

将x-7/x-9分解成1+2/(x-9)其他分式同理则原方程等价于1/x-9+1/x-5=1/x-6+1/x-81/x-6-1/x-5=1/x-9-1/x-81/(x-5)(x-6)=1/(x-8)(

x/(x-2)-2/(x^2-4x+4)=1x/(x-2)-2/{(x-2)(x-2)}=1因为（x-2）不等于0所以约去x-2得x-2/(x-2)=1同分母得{x(x-2)-2}/(x-2)=1x(

你表达的方程的意思是不是x/(x-2)-1=1/(x²-4)那么等式两边同时乘以x²-4,得到x*(x+2)-x²+4=1于是2x=-3解得x=-3/2

解题思路：先解方程求出x，再化简另一分式并把x值代入计算即可解题过程：解：经检验是原方程的解。

Х=1再问：过程？再答：（6x-1）×（2x-5）=（4x-7）×（3x+2）然后拆开，简化最后就得答案了再问：能不能帮忙检验一下，我刚才检验一下，好像不等于1再答：把1带进去，就可以了再问：可代进去

4/5x+x/(5x-25)=5/(x^2-5x)(4x-20)/5x(x-5)+x^2/5x(x-5)=25/5x(x-5)4x-20+x^2=254x+x^2=45x^2+4x+2^2=45(x+

(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)

提负号后,方程两边同乘（x+1）（x-1）得到3（x+1)-4x=-（x-1）,化简的3=1,不成立,即此方程无解

2x^2+3x-4=2x^2+5/(3x)3x-4=5/(3x)9x^2-12x-5=0(3x-5)*(3x+1)=0所以：3x-5=0or3x+1=0解得：x1=5/3,x2=-1/3

令x-2/x=t,则t^2-2t+1=0,t=1,所以x-2/x=1,即x^2-x-2=0,解得x=2,或x=-1

这道题不用那么复杂.先移项.(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/( x-9)再通分.（x-4)(x-6)/(x-5)(x-6)-(x-5)(x

(3x-6)/(x^2+x-6)=(4x+4)/(x^2-3x-4)3(x-2)/[(x+3)(x-2)]=4(x+1)/[(x-4)(x+1)]3/(x+3）=4/(x-4)4(x+3)=3（x-4

左右两边同乘以(X-5)(X-6)(X-8)(X-9)得到(X-4)(X-6)(X-8)(X-9)-(X-5)(X-5)(X-8)(X-9)=(X-5)(X-6)(X-7)(X-9)-(X-5)(X-

第三项的分母是x^2-2x-1吧?2x^2-4x-3/(x^2-2x-1)=32x^2-4x-3-3/(x^2-2x-1)=02(x^2-2x-1)-1-3/(x^2-2x-1)=02(x^2-2x-

1/(x-1)(x-2)=1/(x-4)(x-5)(x-1)(x-2)=(x-4)(x-5)x^-3x+2=x^2-9x+206x=18x=3

(x-2)/(x+2)=(x+2)/(x-2)+16/(x²-4)方程两边同时乘(x²-4)(x-2)²=(x+2)²+16x²-4x+4=x

(5x-4)/(x-2)=(4x+10)/3(x-2)-1两边乘3(x-2)3(5x-4)=4x+10-3(x-2)15x-12=4x+10-3x+615x-12=x+1614x=28x=2经检验,x

3/(x+2)+4/(x-2)=16/(x*x-4)3/(x+2)+4/(x-2)=16/(x+2)(x-2)3(x-2)+4(x+2)=167x=14x=2当x=2.分式的分母为0,此题无意义

由题意知：X不等于0方程可化为4/(X^2+2X+1)+5/(X^2+2X-5)+3/2=0设X^2+2X=Y则:4/(Y+1)+5/(Y-5)+3/2=0然后通分:Y^2-2Y-15=0所以Y=5O

两边同乘x²-4（x-2）²=（x+2）²+16x²-4x+4=x²+4x+4+16-8x=16x=-2