已知|x加3|加(x加2y减1的平方)等于0则2x减y等于
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/08 04:37:25
X+Y=5,XY=2,5X+4Y-3X-2Y+XY=2X+2Y+XY=2(X+Y)+XY=2×5+2=12.
你说的是不是即X=-3 Y=4 那么2X+3Y=6再问:不是不过谢谢我已经会了
∵(x+1)²+|y-2|=0 ∴x+1=0 y-2=0 ∴x=-1 y=2 ∴x²y²+3xy-7x²y²-(5/2)xy+1+5x²
1/x+1/y=2(x+y)/xy=2x+y=2xy(2x-xy+2y)/(3x+5xy+3y)=[2(x+y)-xy]/[3(x+y)+5xy]=(4xy-xy)/(6xy+5xy)=3xy/11x
原式可以写为(X+Y)的平方减2(X+Y)加1等于0.一目了然,X加Y的值是1.
∣x+3∣=-(2x+y)^2,∵∣x+3∣》0,且-(2x+y)^2《0,∴∣x+3∣=(2x+y)^2=0,∴x=-3,y=6∴(3/4)(x^2-3y)+(1/4)(x^2+y)=(3/4)·(
x^2-2x+y^2+6y+10=0x^2-2x+1+y^2+6y+9=0(x-1)^2+(y+3)^2=0x-1=0,y+3=0x=1,y=-3(x-y)/(x+y)=4/(-2)=-2
xy分之x加y等于2∴x+y=2xy3x减5xy加3y分之负x加3xy减y=[-(x+y)+3xy]/[3(x+y)-5xy]=(-2xy+3xy)/(6xy-5xy)=xy/(xy)=1
x^2+y^2+2x-4y+5=0,(x+1)^2+(y-2)^2=0,x=-1,y=2(-1)^2006-1/2=1-1/2=1/2
(x-2)²+|y-1|=0所以x=2,y=1则x+y=33(x+y)²-(x+y)+2*(x+y)²+4=3*9-3+2*9+4=46不知道所求的式子对不对,你说得不明
已知绝对值x加1加y加2括号的平方等于0x+1=0,y+2=0x=-1,y=-23减2xy加3yx的平方加6xy减4x的平方y=3+4xy-x平方y=3+4×1×2-1×(-2)=11+2=13
x^2+3y^2-12y+12=0x^2+3(y-2)^2=0所以x^2=0,3(y-2)^2=0x=0,y-2=0y=2y^x=2^0=1
(x+1)(x+2)(x+3)(x+4)+1=[(x+1)(x+4)][(x+2)(x+3)]+1=(x^2+5x+4)(x^2+5x+6)+1把x^2+5x看做A,所以原式化成:(A+4)(A+6)
直接设X=1,Y=0.5.带入后式得出10
已知x加y等于1,则3减2x减2y=3-2(x+y)=3-2×1=3-2=1;您好,很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,如果满意记得采纳如果有其他问题请采
此题简单做法你直接可以设X=1,Y=0.5,使其满足前面的条件即可,带入后面分式,后面的式子中文表述不清,
x+y-2=x^2+axy+by^2-5x+y+6x+y-2是x^2+axy+by^2-5x+y+6的因式当x+y-2=0时,x^2+axy+by^2-5x+y+6=0令x=y=1,x+y-2=0x^
(x-1)(x+2)(x+3)(x+6)+20=0(x-1)(x+6)(x+2)(x+3)+20=0(x^2+5x-6)(x^2+5x+6)+20=0(x^2+5x)^2-36+20=0(x^2+5x
已知xy/(x+y)=2,求:(3x-5xy+3y)/(-x+3xy-y)xy/(x+y)=2得:xy=2(x+y)(3x-5xy+3y)/(-x+3xy-y)=(3x-9xy+3y+4xy)/(-x