已知y分之x=7分之2
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/10 11:06:29
3/x-2/y=3等式两边同乘以xy3y-2x=3xy(2x-3y-xy)/(7xy+9y-6x)=[-(3y-2x)-xy]/[3(3y-2x)+7xy]=(-3xy-xy)/[3·(3xy)+7x
y=[x/(x-2)-x/(x+2)/2x/(2-x)=4x/(x-2)(x+2)*(2-x)/2x=-2/(x+2)y的值是整数,x+2=1,-1,2,-2x=,-1,-3,0,-4
1/x-1/y=2(y-x)/xy=2y-x=2xy所以x-y=-2xy原式=[2(x-y)+7xy]分之[(y-x)+xy]=[2(-2xy)+7xy]分之[(2xy)+xy]=3xy]分之3xy=
2x-y分之x+y=2,则2x-y=2(x+y)4x-2y分之x+y-4x+4y分之2x-y=2(2x-y)分之x+y-4(x+y)分之2x-y=4(x+y)分之x+y-4(x+y)分之2(x+y)=
x+y分之4x-2y-2x-y分之4x+4y=2(2x-y)/(x+y)-4(x+y)/(2x-y)=2*2-4*(1/2)=4-2=2
x/y=7/2(x²-3xy+2y²)/(x²+2xy+y²)=[(x/y)²-3(x/y)+2]/[(x/y)²+2(x/y)+1]=[(
由x分之1-y分之1=2得到,1/x-1/y=2,即(y-x)/(xy)=2,即x-y=-2xy(1).2x-3xy-2y分之3x+7xy-3y=(2x-3xy-2y)/(3x+7xy-3y)(2)将
x=(√7+√5)/2,y=(√7-√5)/2,xy=1/2,x+y=√7y/x+x/y=(x^2+y^2)/xy=[(x+y)^2-2xy]/xy=(7-1)/(1/2)=12
由题意知令x/4=y/5=z/7=k则x=4ky=5kz=7k∴(2x-y)/z=(2×4k-5k)/(7k)=3/7
1/x+1/y=-2则(x-xy+y)/(x+xy+y)分子分母同除以xy=(1/x+1/y-1)/(1/x+1/y+1)=(-2-1)/(-2+1)=3
因为x+y分之2x-y=2又因为x+y分之4x-2y是它的2倍所以x+y分之4x-2y就=4因为x+y分之2x-y=2倒过来2x-y分之x+y就为1/2又2x-y分之4x+4y是2x-y分之x+y的4
∵(2x+y)/2=(5x+2y)/4=1∴{2x+y=2(1){5x+2y=4(2)(1)==>y=2-2x代入(2)5x+2(2-2x)=4x+4=4,∴x=0,y=2∴(x+2y+1)/(2x-
x+y分之x-y=2求x+y分之3x-3y减x-y分之2(x+y)的值x+y分之x-y=2x-y=2(x+y)(x+y)分之(3x-3y)-(x-y)分之2(x+y)的值x+y分之3x-3y=(x+y
8x/15=7y/12=1,所以x=15/8,y=12/7那么2x+7y=2×(15/8)+7×(12/7)=(15/4)+12=3又4分之3+12=15又4分之3
需要算算,等我哈,
由已知条件可得:x-y=-4xy,(也就是在等式两边乘xy后整理,即可),代入所求的式子里分母为-4xy+7xy,即3xy;分子为-4xy-2xy,即-6xy,化简得-2
因为:3分之x+1=4分之y+3=5分之x+y,所以:(x+1)/3=(y+3)/4=(x+y)/54x+4=3y+94x=3y+55x+5=3x+3y2x=3y-5x=5y=5则x+2y+3分之3x
(x+y)/(x-y)=3/2[(x/y)+1]/[(x/y)-1]=3/23(x/y)-3=2(x/y)+2x/y=5y/x=1/5(x^2+y^2)/xy=x/y+y/x=5+1/5=26/5
原式等价于10(x+1)=5(y+3)=4(x+y)10(x+1)=5(y+3)可得2x-y=15(y+3)=4(x+y)可得4x-y=15解得x=7y=13x+2y+3=363x+2y+1=48两式