已知x=-11, y=-11,用原码一位乘法求[x*y]原
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可以变形为2(X-2)^2+3(y+1)^2=0所以,x=2,y=-1
y=(4x-11)/3x=(11+3Y)/4
实数x,y满足x-4的绝对值+根号y+11=0所以有:X-4=0且Y+11=0得X=4,Y=-11所以,X-Y=4-(-11)=15.
∵x-2y-11+|2x-3y-18|=0,∴x-2y-11=02x-3y-18=0,解得x=3y=-4,∴x-6y=3-6×(-4)=27,∴327=3.
11x-9y-6=0,用x表示y,得y=((11x-6)/9);用y表示x,得x=((9y+6)/11)再问:确定100%全对?再答:嗯
|x|-|x-3.1415926|=0x=1.5707963|y+11/8|-|2y-7.13|=0y=8.505或5.755/3
(x+y)/x=11/88x+8y=11y8x=3yy=8x/3(x-y)/(x+2y)=(x-8x/3)/(x+16x/3)=(-5x/3)/(19x/3)=-5/19
已知x+y=11,则x'2'+x*y=x*(x+y)=11x=99,得到x=9,y=2
因为|2x+y|一定为正数而二次方也是正数而两者和为零即分别等于零所以2x+y=0且3x-11y-5=0所以x=1/5y=-2/5
|2X-Y-3|+(2X+Y+11)的平方=0所以2x-y-3=02x+y+11=0相加得4x+8=0x=-2带入得y=-7所以(-7)^(-2)=1/49
xy+x+y+1=12(x+1)(y+1)=12所以x+1=1,y+1=12或x+1=2,y+1=6或x+1=3,y+1=4或x+1=4,y+1=3或x+1=6,y+1=2或x+1=12,y+1=1所
4x+11y=5x11y=x令y=1则x=112x+y=z22+1=23所以x:y:z=11:1:23
3x+4y=96x+5y=27两式相加得:9x+9y=36则:9(x+y)=36所以,x+y=4所以,11x+11y=11(x+y)=44
(3x-2y)(4x-5y)-11(x+y)(x-y)+5xy=12x^2-23xy+10y^2-11x^2+11y^2+5xy=x^2-18xy+21y^2=x^2-10xy+21y^2-8xy=(
x+y/y=11/8说明11y=8(x+y)即8x=3y所以x-y/x+2y=3(x-y)/3(x+2y)=(3x-3y)/(3x+6y)=(3x-8x)/(3x+16x)=-5/19
已知x+3y+z=11x+y=7,则7x+10y+3z=40
(2x-y)³-(2x-y)²(x-3y)=(2x-y)²[(2x-y)-(x-3y)]=(2x-y)²(x+2y)=10²×11=1100
∵(x+y)²=11∴x²+2xy+y²=11(1)∵(x-y)²=9∴x²-2xy+y²=9(2)(1)+(2)可得2(x²+y
4x²y-3y²=7.(1)3x²y+4y²=19.(2)(1)*2+(2):11x^2y-2y^2=14+19=33
x-y=2-3=-1所以(x-y)*(x-y)^3*(x-y)^5*……*(x-y)^11=(-1)*(-1)²*(-1)²*.(-1)^11=-1*1*(-1)...(-1)=(