已知x y=7,xy=-8,且x>y,则x²-y²的结果为

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已知x-xy=8,xy-y=-9,求x+y-2xy的值

x-xy=8(1)xy-y=-9(2)则有(1)-(2):X-XY-XY+Y=X+Y-2XY=8-(-9)=17

已知xy≠0,且3x²-2xy-8y²=0,求x/y的值

3x^2-2xy-8y^2=0,(3x+4y)(x-2y)=03x+4y=0,或,x-2y=03x=-4y,或,x=2yx/y=-4/3,或,x/y=2

已知实数x、y满足xy>0,且8/xy+1/x+1/y=1,

再问:该方法此处计算是错的,应该为,接下来的都不对了再答:那就从那步开始吧x+y=xy-8若x,y大于0xy-8=x+y≥2√xyxy-8≥2√xyxy-2√xy-8≥0(√xy-4)(√xy+2)≥

已知xy不等于零,且3x^2-2xy-8y^2=0,求x/y的值

3x²-2xy-8y²=0两边同除y²得:3(x/y)²-2(x/y)-8=0(3x/y+4)(x/y-2)=0x/y=2或x/y=-4/3

已知xy>0,且X平方y=2,求x平方+xy的最小值

把他拆成x平方+1/2xy+1/2xy然后利用基本不等式,接下来你应该会做的,我打起来太麻烦

已知 xy不等于0且 3x^2 - 2xy - 8y^2=0求x/y的值!

因为xy不为0,所以3x^2-2xy-8y^2=0可以两边同时除以y^2,得3(x/y)^2-2(x/y)-8=0即(3x/y+4)(x/y-2)=0解得x/y=2或者x/y=-4/3希望有用.

已知x+y=6,xy=1,且x

x+y=6,xy=1,且x

已知xy不等于0,且3x² -2xy-8y²=0,求x/y的值

3x²-2xy-8y²=0(x-2y)(3x+4y)=0x=2y或3x=-4yx/y=2或x/y=-4/3

已知,xy≠0,且3x²-2xy-8y²=0,求x/y的值

xy≠0,所以x≠0,y≠03x²-2xy-8y²=0两边除于xy3(x/y)-2-8(y/x)=0设x/y=t;t≠03t-8/t-2=03t²-2t-8=0(t-2)

已知x+4y=-1,且xy=5,求6xy+8x-【5cy-y+6x】+7y的值

已知x+4y=-1,且xy=5,求6xy+8x-【5cy-y+6x】+7y的值6xy+8x-【5xy-y+6x】+7y=xy+2x+8y=5-2=3

已知|x|=8,|y|=2且xy

∵|x|=8,|y|=2且xy

已知A=8x^2y-6xy^2-3xy,B=7xy^2-2xy+5x^2y,

∵A=8x²y-6xy²-3xy,B=7xy²-2xy+5x²y ∴C=3(A+B)  =3(8x²y-6xy²-3xy+7xy²

已知x,y∈R+,且x+y=1,求证:xy+1xy≥174

∵xy≤(x+y 2)2=14,设xy=t,令f(t)=t+1t,因其f′(t)=1-1t2,当0<t≤14时,f′(t)<0,故函数f(t)在(0,14]上是减函数,∴t+1t≥14+4=

已知x、y都是正数,且xy=4y+x+5,求xy的最小值

因为x、y都是正数,则:x+4y≥4√(xy)设:√(xy)=t,则:xy=4y+x+5≥4√(xy)+5即:t²≥4t+5t²-4t-5≥0t≤-1或t≥5因为:t=√(xy)≥

已知|x|=0.99,|y|=0.09,且xy

|x|=0.99,x=0.99或x=-0.99|y|=0.09,y=0.09或y=-0.09xy

已知x^2-7xy+12y=0,且x.y不等于0,求x^2-2xy+y^2/2xy的值

x^2-7xy+12y=0,且x.y不等于0(x-3y)(x-4y)=0x=3y或x=4y(x^2-2xy+y^2)/(2xy)=(x-y)^2/(2xy)x=3y时原式=4y^2/(6y^2)=2/

已知x-y=3xy,且xy不等于0,则-3x+6xy+3y/(7x-5y)-9xy-(3x-y)

因为,x-y=3xy所以:-3x+6xy+3y/[(7x-5y)-9xy-(3x-y)]=[-3(x-y)+6xy]/[(7x-5y)-9xy-(3x-y)]=[-3*3xy+6xy]/[7x-5y-

已知x-y=4xy且xy≠0,求代数式-x-2xy+y分之2x+3xy-2y的值

∵x-y=4xy∴原式=[2(x-y)+3xy]/[-(x-y)-2xy]=(8xy+3xy)/(-4xy-2xy)=11xy/(-6xy)=-11/6