已知(y-1)(y-2)分之3y 7=y-1分之A y-2分之B求AB的值

x-3y=0x=3y(2x+y)/(x^2-2xy+y^2)÷1/(x-y)=(2x+y)/(x-y)^2÷1/(x-y)=(2x+y)/(x-y)^2*(x-y)=(2x+y)/(x-y)=(2*3

已知1-2y-(y-11)/3=03-6y-y+11=014=7yy=2所以(3y-1)/4+(2y-1)/3=(3*2-1)/4+(2*2-1)/3=5/4+1=9/4再问：3-6y-y+11=0是

2/3

令2分之x=3分之y=4分之z=k,则：x=2ky=3kz=4kx+y+z=1/12,得：2k+3k+4k=1/129k=1/12k=1/108所以：x=2/108=1/54y=3/108=1/36z

∵（2x+y)/2=(5x+2y)/4=1∴{2x+y=2(1){5x+2y=4(2)(1)==>y=2-2x代入（2）5x+2(2-2x)=4x+4=4,∴x=0,y=2∴(x+2y+1)/(2x-

/表示除以x-1/x+2=y-3/y-4题是这样的吗?交叉相乘,（x-1)*(y-4)=(x+2)*(y-3)打开括号,xy-4x-y+4=xy-3x+2y-6-3y=x-10y=10-x/3应该是这

2分之3x+y=14分之5x-y=1,3x+y=2(1)5x-y=14(2)由(1)+(2)式得8x=16x=2y=-42x-3y+7=2*2-3*(-7)+7=32

x+y分之x-y=2求x+y分之3x-3y减x-y分之2(x+y)的值x+y分之x-y=2x-y=2(x+y)(x+y)分之(3x-3y)-(x-y)分之2(x+y)的值x+y分之3x-3y=(x+y

∵3x-2y分之5x+y=2分之1∴（5x+y）×2=（3x-2y）×1【两边同乘以2（3x-2y）,即交叉相乘】∴10x+2y=3x-2y∴10x-3x=2y+2y∴7x=4y.(1)原式x+y分之

1.令x/2=y/3=z/4=k,则有:x=2ky=3kz=4k所以:(2x+y-z)/(x+y+z)=(2×2k+3k-4k)/(2k+3k+4k)=1/32因为x^2+y^2+2x+4y+4=0即

y+1/y=7两边平方得y²+2+1/y²=49∴y²+1/y²=47两边再平方得y的4次方+2+1/y的4次方=47²y的4次方+1/y的4次方=2

x+y=10x-y=8/7原式=-7³/8*(x+y)³*(x-y)*4(x+y)²(x-u)²=-343/2*(x+y)^5*(x-y)³=-343

x:y=2分之1:3分之1=3:2y:z=2:3,所以x:y:z=3:2:3再问：已知x:y=1.5:1，y:z=3分之2:6分之5，求x:y:z，谢谢再答：采纳我，重新问

(3x-4y)÷(2x+y)=1/2所以2x+y=2(3x-4y)=6x-8y4x=9y所以x/y=9/4

因为：3分之x+1=4分之y+3=5分之x+y,所以：（x+1）/3=（y+3）/4=(x+y)/54x+4=3y+94x=3y+55x+5=3x+3y2x=3y-5x=5y=5则x+2y+3分之3x

因为x＋y/2=3x＋4y/5=1,所以x＋y=2,3x＋4y=5所以解方程组得x=3,带入x＋5y＋6/3x－y＋1,得4/11

x=2y/3(4y/3+y-1)/2=(-y/3)/34y+3y-3=-2y/37y-3=-2y/321y-9=-2yy=9/23

(x+y)/2-(x-y)/3=1等式两边同时乘以6,得3(x+y)-2(x-y)=63x+3y-2x+2y=6x+5y=65y=6-xy=(6-x)/5

原式等价于10(x+1)=5(y+3)=4(x+y)10(x+1)=5(y+3)可得2x-y=15(y+3)=4(x+y)可得4x-y=15解得x=7y=13x+2y+3=363x+2y+1=48两式