将下列矩阵化为约化阶梯矩阵

(1)A=112-1211-12212r3-r2,r2-2r1112-10-1-310103r3+r2112-10-1-310032(2)A=115-111-233-18113-97r2-r1,r3-

5+r4,r2+2r1,r3-3r1,r4+4r1101001570-1-3301110-2-2-2r2-r4,r3+r4,r5+2r41010004600-2401110000r3*(-1/2),r

1+r317280-53600515

3-r1-r2,r2-2r1102-100-1300-1-3r3-r2102-100-13000-6r3*(-1/6),r1+r3,r2-3r3102000-100001r1+2r2,r2*(-1)1

1+r214-135432306-1-50-725141r2-4r1,r3-6r1,r4-2r114-1350-136-9-200-251-18-370-33-2-9r3-2r214-1350-136

b=[135-40;132-21;1-21-1-1;1-411-1];>>rref(b)ans=1.00000000.500001.0000000.5000001.0000000001.00000.5

1-r4,r2-2r4,r4-4r40-17-60-17-60-214-1210-45r2-r1,r3-2r10-17-60000000010-45交换行10-450-17-600000000

3*(1/3)1312477123r1-r3,r2-4r30190-1-5123r2+r1019004123交换行123019004因为各教材中"约化阶梯行"的名称不一,估计这是你要的结果又称为梯矩阵

1-13-12-1-143-22310-45r1-r4,r2-2r4,r3-3r40-17-60-17-60-214-1210-45r2-r1,r3-2r1,r1*(-1)0-17-600000000

1-r4,r2-2r4,r4-4r40-17-60-17-60-214-1210-45r2-r1,r3-2r10-17-60000000010-45r1*(-1),交换行10-4501-7600000

解:A=112210215-1203-131104-1r3-2r1,r4-r1112210215-10-2-1-5100-22-2r3+r2,r4*(-1/2)112210215-100000001-

先找出第一列数的规律,例如（开始化简时应该先观察其中行与行之间有无成倍数关系的若有可直接使其中一行为0）2356414512343679这个矩阵可以用第2行减去第4行（4-3后能得到1这样有利于后续化

把每行的第一个化成1,再相减,然后倍乘,再将第2列化为1,如此下去即可.

因为名称不一,约化阶梯形我理解为行阶梯矩阵1.r3+r117280-536005152.解:r1-r4,r2-2r4,r4-4r40-17-60-17-60-214-1210-45r2-r1,r3-2

(1)A=112-1211-12212r3-r2,r2-2r1112-10-1-310103r3+r2112-10-1-310032(2)A=115-111-233-18113-97r2-r1,r3-

A-->r3+r117280-53600515r3*(1/5),r1-2r3,r2-3r317020-50-30013r2*(-1/5),r1-7r2100-11/50103/50013

3行4列还是4行3列再问：3行4列再答：r3+r117280-53600515r3*(1/5)17280-5360013r1-2r3,r2-3r317020-50-30013r2*(-1/5)1702

1-3r2,r3-r2,r4+2r2-70-726312-710-513708-21r1+r4,r4-7r30015312-710-5130043-112r4-43r10015312-710-5130

1-12102-2420306-1130631r4-r3,r2-2r1,r3-3r11-121000000030-4100040r2+r3,r4*(1/4),r1-r41-12000000003001