7x-4y=3

（x+5y）（x+4y）-（x-y）（x+y）=x²＋9xy＋20y²-x²＋y²=9xy＋21y²=9×（-2又2/3×3/7）＋21×（3/7）&

3x+2=y和11x=y,得到x=1/4,y=11/4,5X+4=Y和7X+6=Y,得到X=-1,Y=-1代入9X+8=y,不成立,方程组无解..

3(x+y)+3(y-x)=1(1)3(x+y)+4(y-x)=-1(2)(2)-(1)得y-x=-2(3)代入（1）3（x+y)-6=1x+y=7/3=>x=7/3－y又由（3）得x=y+2y+2=

把x=3带入6+3y分之21-4y=6-2y分之6+2y(6+3y)(6+2y)=(21-4y)(6-2y)3y^-84y+90=0

根号(x+y-8)+根号(8-x-y)=根号(3x-y-4)+根号(x-2y+7),根据二次根式有意义得：X+Y-8≥0,8-X-Y≥0,∴X+Y≥8,X+Y≤8,∴X+Y=8,左边为0,右边两个非负

原式=(x^2-y^2)(x^2+8xy+16y^2)+(x+4y)*y代入值即可很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,

将11x=y即y=11x分别代入前面四个方程式,1、方程式一得3x+2=11x,x=1/4,则y=11/4；2、方程式二得5x+4=11x,x=2/3,则y=22/3；3、方程式二得7x+6=11x,

原式=(x''+9xy+20y'')(x''-y'')带入数据得：(64/9-72/7+180/49)*(64/9-9/49)再通分=((3136-4536+1260)/441)*(3136-81)/

3(X-Y)²-4(X-Y)+7(X-Y)-6(X-Y)²=(3-6)(X-Y)²+(-4+7)(X-Y)=-3(X-Y)²+3(X-Y)

(7x-2y)(3x-2y-1)-(4x+3y)(9x+6y)=21x^2-14xy-7x-6xy+4y^2+2y-36x^2-24xy-27xy-18y^2=-15x^2-70xy-7x-14y^2

3(x+y)-4(x-y)=4(x+y)/2+(x-y)/6=1令a=x+y,b=x-y3a-4b=4(1)a/2+b/6=1则3a+b=6(2)(2)-(1)5b=2b=2/5a=(6-b)/3=2

最后一个应该是：y-11x=10吧这样解就是X=-1,Y=-1否则无解

（5x+3y)(3y-5x)-(4x-y)(4y+x)=(3y)^2-(5x)^2-(4x^2+15xy-4y^2)=9y^2-25x^2-4x^2-15xy+4y^2=13y^2-15xy-29x^

3X+4Y=23X=2-4YX=(2-4Y)/3X-Y-1/7D

x=-1,y=2

x（x*x-1)+x(5-x*x)-6y+7=-x+5x-6y+7=2(2x-3y)+7=2*(-4)+7=-8+7=-1再问：能在写详一点吗-x+5x-6y+7再答：x（x*x-1)+x(5-x*x

(3x-4y)(5x-4y)-(7x-8y)(6y-5x)=15x²-12xy-20xy+16y²-（42xy-35x²-48y²+40xy）=15x²

x-4y分之3x+4y-x分之x+y-x-4y分之7y=3x/(x-4y)-(x+y)/(x-4y)-7y/(x-4y)=(3x-x-y-7y)/(x-4y)=(2x-8y)/(x-4y)=2

3x+2=y5x+4=y7x+6=y9x+8=y有解x=-1,y=-111x=y按前面的规律,是不是少加了一个10?应该是11x+10=y?是的话,解就是x=-1,y=-1了

因为8/(x+y)+18/(x-y)=4/3,两边乘以3得24/(x+y)+54/(x-y)=4两边同时减去24/(x+y)+24/(x-y)=7/3得30/(x-y)=5/3所以x-y=18代入8/