定义函数total(n)计算1 2 3 --. n,函数返回值类型是int.-搜答案-智慧作业帮

#include"stdio.h"intfact1(intn){if(n==1||n==0)return1;elsereturnn*fact1(n-1);}intfact2(intn){inti,t=

intjie_cheng(intn){if(n==1)return1;returnn*jie_cheng(n-1);}doublefact(intn){doublesum=0;for(inti=1;i

vars:real;n:longint;functionjc(x:longint):longint;vari:longint;beginjc:=1;fori:=2toxdojc:=jc*i;end;f

f(n)=(3n-1)(n)/2=3n²/2-n/2

试试下面这个#includevoidmain(void){doublefunc(int);doubles=0,term;inti;for(i=0,term=1;;i++){term=1.

#includedoublefact(intn){doubles=1.0;inti;for(i=1;i

#include"stdio.h"doublef(int){if(n>0);doublem=0.0;for(inti=0;i

publicclassTest{　　publicstaticvoidmain(String[]args){　　doublen=10;　　doubleresult=fmethod(n);　　System

a=a+1.0/tota(n);

#includeusingnamespacestd;intpow(intx,intn){if(n==0)return1;elsereturnpow(x,n-1)*x;}voidmain(){intx,

inttotal(intn){returnfact(n);}intfact(intn){if(n==1)return1;elsereturnn+fact(n-1);}

vars,ans:int64;i:longint;beginreadln(s);fori:=1tosdoinc(ans,facto(i));writeln(ans);end.也许需要高精度!当s>=1

#include "stdio.h"int total(int n){ int sum=0; i

intsun=1;//计算阶乘的值intsum=0;//累加for(inti=0;i

C描述functionttt(n){ returnn>1?n*ttt(n-1):1;}使用方法:ttt(21);

doublefact(intn){doubletemp;if(n==0||n==1)return1.0;if(n>=2){temp=double(n*fact(n-1));rentuntemp;}}

#includeintmain(){intn;doublem;doublefac(intn);scanf("%d",&n);m=fac(n);printf("%d!=%f\n",n,m);return

publicinttotal(intn){intresult=0;for(inti=1;i

//阶乘函数intfactorial(intn){if(n>n;ints=1;while(n>1){s+=1/factorial(n--);}cout

java版实现public class Calculator{ public int calTest(int&nb