6 (x÷3)=(5-2x)÷2的值是多少

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/11 18:25:16
两道初二数学计算题(1)x+6/x^2+2x+1-x+4/x^2+x=0(2)x+3/x÷x^2+3x/x-3·1/3-

(1)(x+6)/(x^2+2x+1)-(x+4)/(x^2+x)=0(x+6)/(x+1)²-(x+4)/[x(x+1)]=0都乘以x(x+1)²得,x(x+6)-(x+4)(x

(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3

(x+1-1/1-x)÷(x-x²/x-1)=[(x+1)+1/(x-1)]×[-(x-1)/x(x-1)]=(x²-1+1)/(x-1)×(-1/x)=-x/(x-1)(x-4/

(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8

1)(x-3)/(x-2)-(x-5)/(x-4)=(x-7)/(x-6)-(x-9)/(x-8)化简得【(x-3)(x-4)-(x-5)/(x-2)】/【(x-2)(x-4)】=【(x-7)(x-8

x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?

x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊

2x+3x+4x+5x+x+6x+7x=100

2x+3x+4x+5x+x+6x+7x=10028x=100x=100/28x=25/7

6÷(x-1)+3÷x=(x+5)÷(x∧2-x)

两边乘x(x-1)6x-3(x-1)=x+56x-3x+3=x+52x=2x=1经检验,x=1时分母x-1=0是增根舍去所以方程无解

先化简再求值:(x+2/x²-2x - x-1/x²-4x+4)÷ x-4/x,其中x=3/2

(x+2/x²-2x-x-1/x²-4x+4)÷x-4/x={(x+2)(x-2)/[x(x-2)²]-x(x-1)/[x(x-2)²]}·x/(x-4)={(

已知(x-根号2+1)(x-2)=0,求代数式[(x-1)/(x-3)-(x-4)/x]÷(x^2+x-6)/(x^2+

注意:本题x=2时题目没意义,应该舍去(这是很多学生错误所在)这里x只能取根号2-1  

6/(x+1)=(x+5)/[x(x+1)] (3-x)/(x-4)+1/(4-x)=1 2/(1+x)-3/(1-x)

6/(x+1)=(x+5)/[x(x+1)]6x=(x+5)(两边同乘x(x+1))5x=5(合并同类项)x=1(3-x)/(x-4)+1/(4-x)=1(3-x)-1=(x-4)(两边同乘(x-4)

2x^2-4x/x+2`x^2+2x/x^2-4x+4÷x/3x-6,其中x=根号3/2

原式=2x(x-2)/(x+2)×x(x+2)/(x-2)²×3(x-2)/x=6x当x=√3/2时原式=3√3

解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

计算:(x^3-3x^2)/(x^2+5x+6)÷(x^3-9x)/(x^2+2x-3)*(x+2)/(2x)

1.(x^3-3x^2)/(x^2+5x+6)÷(x^3-9x)/(x^2+2x-3)*(x+2)/(2x)=x^2(x-3)/(x+2)(x+3)*(x+3)(x-1)/x(x+3)(x-3)*(x

5x-3(2x+1)=6x-4(5-3x)求x

5x-3(2x+1)=6x-4(5-3x)求x5x-6x-3=6x-20+12x20-3=6x+12x-5x+6x19x=17x=17/19

初一数学x*x+2x+5的值为7,请求3x*x+6x+3的值.因为x*x+2x2x+3=3x(x*x+2x)+2x+2x

x^2+2x+5=7所以x^2+2x=23x^2+6x+3=3(x^2+2x)+3=3*2+3=9再问:2怎么会变6?再答:3x^2+6x+3是题目给的x^2+2x=2是我根据题意化简得来的再问:??

((x²-5x+6)/(12-7x+x²))²÷((x²+3x+2)/(x

原式化简:{(x-3)(x-2)/(x-3)(x-4)}²÷{(x+1)(x+2)/(x-4)(x+2)}²{(x-2)/(x-4)}²÷{(x+1)/(x-4)}

先化简,再求值(2x-6)/(4-4x+x^2)÷ (x+3)× (x^2+x-6)/(3-x),其中x=-1/2

原式=2(x-3)/(x-2)²×1/(x+3)×(x-2)(x+3)/[-(x-3)]=-2/(x-2)当x=-1/2时原式=-2/(-5/2)=4/5

(x³-1)÷(x-1)=?(9x³-6x²-5x+2)÷(3x-1)=?计算

原式=(x-1)(x的平方+x+1)÷(x-1)=x的平方+x+1原式=(9x立方-6x平方+x-6x+2﹚÷﹙3x-1﹚=[x(3x-1)平方-2(3x-1)]÷﹙3x-1﹚=x(3x-1)-2=3

已知x²+3x-1=0,求(x-3)/(3x²-6x)÷(x+2-5/(x+2))的值

x²+3x-1=0x²+3x=1(x-3)/3x²-6x)/[(x+2-5/(x-2)]={(x-3)/[3x(x-2)]}/{[(x+2)(x-2)-5]/(x-2)]