5,55,555求和的c语言代码

#includeintmain(){\x09intsum=0;\x09for(inti=1;i

呵呵,你怎么在提了同样的问题,这两个是别人解答的,如果不满意,我加修改.#include"stdio.h"voidmain(){intn,sum=0;while(1){scanf("%d",&n);i

#includeintmain(){intt=1;inti;ints=0;for(i=2;i

intsum(intm,intn){inti=m;intsum=m;if(m>n){printf("\nAmistake:m=%d>n=%d\n",m,n);return;}else{while(i{

#includeintmain(){inti;intn,a,s,temp;scanf("%d%d",&n,&a);s=a;temp=a;for(i=2;i

floatsum=0.0f;floatu,a,b;while(1){scanf("%f%f",&u,&a);b=u+a;sum+=b;printf("这里是每次输入和:%f",b);printf("这

输入两个整数,中间空格：#include<stdio.h>main(){\x09int a,b;\x09printf("Input a,b:\n")

#includeintmain(){intn,i;while(scanf("%d",&n)!=EOF)/使用EOF/{longsum=0;for(i=1;i

两个函数求和?是两个数求和的函数吧!intadd(inta,intb){returna+b;}intmain(){intsum;int(*fn)(int,int);fn=add;sum=fn(3,5)

楼上的有点错误,我给改了一下,可以直接编译运行：#include#defineN10//前10项的和intmain(){inta=5,s=5,tmp=0;intsum=0;for(inti=0;i{s

楼主贴代码,我好给你改啊#include<stdio.h>int main (void){    int sum&nb

#includeintmain(){\x09inti,sum=0;\x09for(i=1;i

为了方便,用整数相加举例.#includevoidmain(){inta,b,c,sum;printf("请输入3个数用来相加:\n");scanf("%d%d%d",&a,&b,&c);sum=a+

#include <stdio.h>int main(){int a,b;scanf("%d%d",&a,&b);prin

#includeintmain(){\x05intn;//\x05printf("请输入一个十位数:");\x05scanf("%d",&n);\x05printf("%d",n%10+n/10);}

#include<stdio.h>void main(){\x09int i, n, sum = 0;\x09int 

同学,20!就已经很大了,你定义sum为int无法保存结果,而且,阶乘不是那样子写的.#include"stdio.h"doublejiecheng(intn){if(n==0||n==1)retur

循环条件里可以有scanf.这样while(scanf("%d",&n)!=EOF)就可以#includeintmain(){intn,a,i,s;while(scanf("%d",&n)!=EOF)

#includevoidmain(){inti,j;inttemp,res1=0,res2=0;for(i=0;i

#include#includeintmain(void){\x05intm;\x05scanf("%d",&m);\x05while(m--){\x05\x05intn,i;\x05\x05doub