复数集内因式分解 x^4 x^2y^2 y^4-搜答案-智慧作业帮

x^6-y^6=（x^3+y^3）（x^3-y^3）=(x+y)(x-y)(x^2+xy+y^2)(x^2xy+y^2)=(x+y)(x-y)(x^2+xy+y^2/4+3*y^2/4)(x^2-xy

（x^2+y^2)-4x^2y^2=[(x^2+y^2)+2xy][(x^2+y^2)-2xy]=(x^2+2xy+y^2)(x^2-2xy+y^2)=(x+y)^2*(x-y)^2

x^2-2x-4y^2-4y=(x^2-4y^2)-(2x+4y)=(x+2y)(x-2y)-2(x+2y)=(x+2y)(x-2y-2)

4x^3-4x^2y-(x-y)=4x^2(x-y)-(x-y)=(x-y)(4x^2-1)=(x-y)(2x-1)(2x+1)

4x^3-4x^2y-(x-y)=4x²(x-y)-(x-y)=(x-y)（4x²-1）=(x-y)(2x+1)(2x-1)再问：a^3+1/81(b^3)x(x+4)+4x的绝对

x²+5y²=x²-5i²y²=(x-√5iy)(x+√5iy)

x^2-2y-4y^2+x=(x^2-4y^2)+(x-2y)(第一个括号中用平方差公式)=(x+2y)(x-2y)+(x-2y)(提出公因子x-2y)=(x+2y+1)(x-2y)

x(x-y)+4(y-x)=x(x-y)-4(x-y)=(x-y)(x-4)=(x-y)(X+2)(X-2)

不能分解

x^3-1=(x-1)(x^2+x+1)=0.25(x-1)(2x+1-isqrt(3))(2x+1+isqrt(3))

原式=(x^2+x)-(4y^2-2y)=(x^2+x+1/4-1/4)-(4y^2-2y+1/4-1/4)=[(x+1/2)^2-1/4]-[(2y-1/2)^2-1/4]=(x+1/2)^2-1/

x^2-y^2-2x-4y-3=(x-1)^2-(y^2+4y+4)=(x-1)^2-(y+2)^2=(x-1+y+2)*(x-1-y-2)=(x+y+1)*(x-y-3)

4（x-y+1)+y(y-2x)=4x-4y+4+y^2-2xy=(y^2-4y+4)-2x(2-y)=(y-2)^2+2x(y-2)=(y-2)(2x+y-2)

x^2(x^2-y^2)-12y^4=x^4-x^2y^2-12y^4=(x^2-4y^2)(x^2+3y^2)您好,很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,

4x(y-x)-y^2因式分解

4x(y-x)-y²=4xy-4x²-y²=-(4x²-4xy+y²)=-(2x-y)²很高兴为您解答,【the1990】团队为您答题.请点

原式=x^2+4x-(y+3)(y-1)1(y+3)1-(y-1)(y=3)-(y-1)=4故原式=(x+y+3)(x-y+1)小结：遇到两元甚至多元的问题,要善于利用主元法,将其中一个字母当成元,其

3x^4+x^2y-2y^2=(3x²-2y)(x²+y)

原式=(x+2y)(x-2y)-(x+2y)=(x+2y)(x-2y-1)

x^2y-4y因式分解

x^2y-4y=y(x^2-4)=y(x^2-2^2)=y(x+2)(x-2)如果帮到你,请记得采纳,O(∩_∩)O谢谢

x^2+4xy+4y^2+3x+6y-18=(x^2+4xy+4y^2)+3(x+2y)-18=(x+2y)^2+3(x+2y)-18=(x+2y+6)(x+2y-3)