因式分解解方程5x[x-2]-4[2-x]=0-搜答案-智慧作业帮

3x²+5x=0x(3x+5)=0∴x=0x=-5/3(2a-1)²=02a-1=0a=1/2(2x-5)²=92x-5=32x-5=-3x=4x=1(2x+x-1)(2

2x²+x-1=0(2x-1)(x+1)=02x-1=0或x+1=0x1=1/2x2=-1

解由（根号3+1）x^2=2x得（√3+1）x^2=2x即（√3+1）x^2-2x=0即x[（√3+1）x-2]=0即x=0或（√3+1）x-2=0即x=0或x=2/(√3+1)=2(√3-1)/(√

错了改一下(2x+5)²-6(2x+5)+9=0[(2x+5)-3]²=0(2x+2)²=02x+2=0x=-1

5x平方-2x-7=0(5x-7)(x+2)=0x1=7/5x2=-2

1/2x²+x+1/2=0x²+2x+1=0（x+1）²=0解得：x=-1

3x²‐2x＝0x（3x-2）=0则x=0或3x-2=0,x=2/3应该是这样的吧

9（x-1）²-（x+2）²=09（x-1）²=（x+2）²3（x-1）=x+2或3（x-1）=-x-23x-3=x+2或3x-3=-x-22x=5或4x=1x

x(x-2)=0x=0,x=2再问：（y－5）（y＋7）？？

x^2+2x-4=0(x^2+2x+1)-5=0(x+1)^2-5=0(x+1+√5)(x+1-√5)=0x1=-1-√5x2=-1+√5

1/2x²+2x+½=½*(x²+4x+1)=½*[(x+2)²-3]=½*(x+2+根号3)(x+2-根号3).方程（5x+6）

（2x+1）²=2(2x+1）（2x+1）²-2(2x+1）=0（2x+1)(2x+1-2)=0(2x+1)(2x-1)=0x1=-1/2,x2=1/2再问：（2x+1）²

5x²－4x＝0x﹙5x－4﹚＝0x1＝0x2＝4/5.

移项4x²-1=0(2x+1)(2x-1)=0x=-1/2,x=1/2

(3x+1)(x-1)=(2x-5)(x-1)(3x+1)(x-1)-(2x-5)(x-1)=0(x-1)(3x+1-2x+5)=0(x-1)(x+6)=0x=1,x=-6

(5x-3)^2=(2x+1)^25x-3=2x+1或5x-3=-2x-13x=4或7x=2x=4/3或x=2/73(x+3)^2=x^2+x3x²+18x+27=x²+x2x&#

(x-1)(2x+3)+x(1-x)=0(x-1)(2x+3)-x(x-1)=0(x-1)(2x+3-x)=0(x-1)(x+3)=0x-1=0x=1x+3=0x=-3

1/2x^2+5x-3=0x^2+10x-6=0x^2+10x+25=31（x+5）^2=31(x+5+根31)(x+5-根31)=0x=-5-根31或=-5+根31

应该是3(1/2-x)²-5(x-1/2)-2=0则3(x-1/2)²-5(x-1/2)-2=0[3(x-1/2)+1][(x-1/2)-2]=0(3x-1/2)(x-5/2)=0