因式分解x平方-2x(y-z) (y z)平方-搜答案-智慧作业帮

可以使用平方差公式：m^2-n^2=(m+n)(m-n)所以(2x＋y)^2-(x+2y)^2=（2x＋y+x+2y)(2x＋y-x-2y）=(3x+3y)(x-y)=3(x+y)(x-y)

x^2(y-z)+y^2(z-x)+z^2(x-y)=x^2y-x^2z+y^2z-y^2x+z^2x-z^2y=y(x^2-z^2)-xz(x-z)-y^2(x-z)=y(x+z)(x-z)-xz(

9x²y²-16z²=(3xy+4z)(3xy-4z)平方差公式

=(x+y+z)^2+yz(y+z+x)=(x+y+z)(x+y+z+yz)

(z²-x²-y²)-4x²y²=(z²-x²-y²-2xy)(z²-x²-y²+2xy)

(x+2y)的平方-4x的平方=(x+2y+2x)(x+2y-2x)=(3x+2y)(2y-x)

题目是否错了应该改为(x+y+z)^2-4(x-y-z)^2(x+y+z)^2-4(x-y-z)^2=[(x+y+z)-2(x-y-z)][(x+y+z)+2(x-y-z)]=(3Y+3Z-X)(3X

设a=x-y,b=y-z,-a-b=z-x(y-z)平方+(x-y)平方+(z-x)平方=(y+z-2x)平方+(z+x-2y)平方+(x+y-2z)平方b^2+a^2+(-a-b)^2=(-a-b-

原式=(x+y)(x-y)+z(x-y)=(x-y)(x+y+z)=0

(x-y)平方+2y(x-y)=(x-y)(x-y+2y)=(x-y)(x+y)

(4x-3y)²-16y²=(4x-3y+4y)(4x-3y-4y)=(4x+y)(4x-7y)x²+2x(y-z)+(z-y)²=x²+2x(y-z

(a-b)+x平方(b-a)=(a-b)-x^2(a-b)=(a-b)(1-x^2)=(a-b)(1-x)(1+x)4M平方—（m+n)平方=(2m)^2-(m+n)^2=(2m-m-n)(2m+m+

原式=x^3+2x^2y+xy^2 =x(x^2+2xy+y^2) =x(x+y)^2再问：x-2��֮x-

（1）因式分x²-y²-2x-4y-3=(x-1)²-(y+2)²=(x-1+y+2)(x-1-y-2)=(x+y+1)(x-y-3)（2）因式分x²

xy+y平方+x-y-2=xy+x+y^2-y-2=x(y+1)+(y+1)(y-2)=(y+1)(x+y-2)

x²-(x-y)²=[x+(x-y)][x-(x-y)]=y(2x-y)9a²-4(b+c)²=[3a+2(b+c)][3a-2(b+c)]=(3a+2b+2c

25xy^2z^2(x+y-z)-30xyz(z-x-y)^2+5xyz^3(z-x-y)=25xy^2z^2(x+y-z)+30xyz(x+y-z)^2-5xyz^3(x+y-z)=5xyz(x+y

x^2-2xy+y^2-9z^2=(x-y)^2-(3z)^2=(x-y+3z)(x-y-3z)

x平方-4y平方-x-2y=(x+2y)(x-2y)-(x+2y)=(x+2y)(x-2y-1)