因式分解56x³yz 14x²y²z-21xy²z²
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﹙x+y)²-﹙x+y)-56=(x+y+7)(x+y-8)用十字相乘法x+y+7x+y-8
原式=(x-y)2+4(x-y)+4=(x-y+2)2说明:2表示平方
(x+1)(y+1)
解题思路:提取公因式进行分解解题过程:附件最终答案:略
原式=-(x-y)³(x-y-1)
(x-y)^2-(x-y)^3=(x-y)^2[1-(x-y)]=(x-y)^2(1-x+y)2.(x+y)^2-(x+y)^3=(x+y)^2[1-(x+y)]=(x+y)^2(1-x-y)3、(x
x(x-y)+4(y-x)=x(x-y)-4(x-y)=(x-y)(x-4)=(x-y)(X+2)(X-2)
x²+y-xy-x=﹙x²-xy﹚+﹙y-x﹚=x﹙x-y﹚-﹙x-y﹚=﹙x-y﹚﹙x-1﹚
原式=(x+y)²+(x+y)-6=(x+y+3)(x+y-2)
1-x-y+xy=(1-x)-(y-xy)=(1-x)-y(1-x)=(1-x)(1-y)
=(x+y)(x-y)-(x+y)=(x+y)(x-y-1)
4x(y-x)-y²=4xy-4x²-y²=-(4x²-4xy+y²)=-(2x-y)²很高兴为您解答,【the1990】团队为您答题.请点
xy-x-y+1=x(y-1)-y+1=x(y-1)-(y-1)=(y-1)(x-1)
x^4-y^4=(x²-y²)(x²+y²)=(x-y)(x+y)(x²+y²)
(x-y(x-y-1)
(x-1)(y-1)
您好:x方(x-y)+(y-x)=x方(x-y)-(x-y)=(x²-1)(x-y)=(x+1)(x-1)(x-y)如果本题有什么不明白可以追问,如果满意记得采纳如果有其他问题请采纳本题后另
这个不能分解的,题目错了
原式=x²(x-y)-(x-y)=(x²-1)(x-y)=(x+1)(x-1)(x-y)
xx-yy-x-y=(x^2-y^2)-(x+y)=(x+y)(x-y)-(x+y)=(x+y)(x-y-1)