因式分解4x²-4xy-8y-8x 10y 3-搜答案-智慧作业帮

解原式=x(x^2+4xy+4y^2)=x(x+2y)^2再答：不用谢

16x²y-16x³-4xy=4x(4xy-4x²-y)再问：只能分解到这吧？再答：因为你的最后一项是4xy如果是4xy²的话，还能继续分解再问：哦，我也觉得可

－x²y－4xy－4y=－y(x²＋4x＋4)=－y(x＋2)²

x^3-2x^2y-4xy^2+8y^3=(x^3-2x^2y)+(-4xy^2+8y^3)=x²(x-2y)-4y²(x-2y)=(x-2y)(x²-4y²)

4xy²-4x²y-y^3=y(4xy-4x²-y²)=-y(4x²-4xy+y²)=-y(2x-y)²

4x2y+4xy+y=y(4x2+4x+1)=y(2x+1)2

x的平方-xy-4x+4y=x(x-y)-4(x-y)=(x-y)(x-4)

解3x²y+6xy-4x-8=(3x²y-4x)+(6xy-8)=x(3xy-4)+2(3xy-4)=(x+2)(3xy-4)

=x(4x²-4xy+y²)先提公因式=x(2x-y)²再用完全平方公式分解

(2-2xy)(2x-1)

题目有错?x^3-4xy^2-2x^2y+8y?x^3-4xy^2-2x^2y+8y^3?(x+2y)^3=x^3+6x^2y+12xy^2+8y^3,x^3-4xy^2-2x^2y+8y^3=(x+

=(xy-2)(xy+2)+y(xy-2)=(xy-2)(xy+2+y)

x²-y²+4xy=（x²+4xy+4y²）-5y²=(x+2y)²-5y²=(x+2y+√5y)(x+2y-√5y)如果本题有什

原式=3x(x-2y)-4(x-2y)=(x-2y)(3x-4)

4x^3y-8x^2y+3xy^3=xy(4x^2-8xy+3y^2)=xy(2x-3y)(2x-y)

4x²y+4xy²+xy²=xy(4x+4y+y)=xy(4x+5y)ps：题是不是写错了?再问：木有写错啊考试题出的就是这个再答：那就是这个答案了~~我奇怪的是4x&#

原式=(x-2y)^-z^=(x-2y-z)(x-2y+z)

-4xy＋x²y＋4y=y(x²-4x+4)=y(x-2)²

-x³-4xy²+4x²y=-x(x²-4xy+4y²)=-x(x-2y)²

x^2--xy+4x--4y=x(x-y)+4(x-y)=(x+4)(x-y)