因式分解4x-4y-x^2 y^2

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(x-y)(x-y+4)+4因式分解

原式=(x-y)2+4(x-y)+4=(x-y+2)2说明:2表示平方

(x^2+y^2)-4x^2y^2因式分解

(x^2+y^2)-4x^2y^2=[(x^2+y^2)+2xy][(x^2+y^2)-2xy]=(x^2+2xy+y^2)(x^2-2xy+y^2)=(x+y)^2*(x-y)^2

(x-y)^3-(x-y)^4 因式分解

原式=-(x-y)³(x-y-1)

x^2-2x-4y^2-4y 因式分解

x^2-2x-4y^2-4y=(x^2-4y^2)-(2x+4y)=(x+2y)(x-2y)-2(x+2y)=(x+2y)(x-2y-2)

4x*3-4x*2y-(x-y)因式分解

4x^3-4x^2y-(x-y)=4x^2(x-y)-(x-y)=(x-y)(4x^2-1)=(x-y)(2x-1)(2x+1)

因式分解4x²-2y+4x-y²

4x²-2y+4x-y²=4x²-y²+4x-2y=(2x+y)(2x-y)+2(2x-y)=(2x-y)(2x+y+2)

4x^3-4x^2y-(x-y)因式分解

4x^3-4x^2y-(x-y)=4x²(x-y)-(x-y)=(x-y)(4x²-1)=(x-y)(2x+1)(2x-1)再问:a^3+1/81(b^3)x(x+4)+4x的绝对

x^2-2y-4y^2+x因式分解!

x^2-2y-4y^2+x=(x^2-4y^2)+(x-2y)(第一个括号中用平方差公式)=(x+2y)(x-2y)+(x-2y)(提出公因子x-2y)=(x+2y+1)(x-2y)

x(x-y)+4(y-x)因式分解

x(x-y)+4(y-x)=x(x-y)-4(x-y)=(x-y)(x-4)=(x-y)(X+2)(X-2)

4x²-y²-4x +2y因式分解

4x²-y²-4x+2y=(2x+y)(2x-y)-2(2x-y)=(2x-y)(2x+y-2)c²-a²+2ab-b²=c²-(a-b)&

x^2+x+2y-4y^2 因式分解

原式=(x^2+x)-(4y^2-2y)=(x^2+x+1/4-1/4)-(4y^2-2y+1/4-1/4)=[(x+1/2)^2-1/4]-[(2y-1/2)^2-1/4]=(x+1/2)^2-1/

x^2-y^2-2x-4y-3因式分解

x^2-y^2-2x-4y-3=(x-1)^2-(y^2+4y+4)=(x-1)^2-(y+2)^2=(x-1+y+2)*(x-1-y-2)=(x+y+1)*(x-y-3)

把4(x-y+1)+y(y-2x)因式分解

4(x-y+1)+y(y-2x)=4x-4y+4+y^2-2xy=(y^2-4y+4)-2x(2-y)=(y-2)^2+2x(y-2)=(y-2)(2x+y-2)

因式分解:(x-2y)-4x+8y+4

(x-2y)²-4x+8y+4=(x-2y)²-4(x-2y)+4=(x-2y-2)²

4x(y-x)-y^2因式分解

4x(y-x)-y²=4xy-4x²-y²=-(4x²-4xy+y²)=-(2x-y)²很高兴为您解答,【the1990】团队为您答题.请点

(x+y)^4(x-y)^2-(x+y)^2(y-x)^4因式分解

(x+y)^4(x-y)^2-(x+y)^2(y-x)^4=(x+y)^4(x-y)^2-(x+y)^2(x-y)^4=(x+y)^2(x-y)^2[(x+y)^2-(x-y)^2]=4xy(x+y)

x^2y-4y因式分解

x^2y-4y=y(x^2-4)=y(x^2-2^2)=y(x+2)(x-2)如果帮到你,请记得采纳,O(∩_∩)O谢谢

(x-2y)²+4x-8y+4 因式分解

(x-2y)²+4x-8y+4=(x-2y)²+4(x-2y)+4=[(x-2y)+2]²a³-a²-a+1=a²(a-1)-(a-1)=(

因式分解:2x^4y^4-x^8-y^8

2x^4y^4-x^8-y^8=-(x^8-2x^4y^4+y^8)=-(x^4-y^4)^2=-(x^2+y^2)^2(x+y)^2(x-y)^2