4*X^2-9*Y^2

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{(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y

(x-y)(z+y-x+y+2y)÷4y=(x-y)(z-x+4y)÷4y{(x+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y=(x-y)(x+y-x+y+2y)÷4y=(x-y)(4

4(x+y)^2-9(x-y)^2因式分解,

利用平方差公式:a²-b²=(a+b)(a-b)4(x+y)²-9(x-y)²=[2(x+y)]²-[3(x-y)]²=[2(x+y)+3(

4-12(x-y)+9(x+y)^2

4-12(x-y)+9(x+y)^2=[3(x+y)]^2-12xy+2^2=[3(x+y)-2]^2=(3x+3y-2)^2

x^2-y^2/x+y-4x(x-y)+y^2/2x-y,

(x^2-y^2)/(x+y)-(4x(x-y)+y^2)/(2x-y)=(x-y)(x+y)/(x+y)-(4x^2-4xy+y^2)/(2x-y)=(x-y)-(2x-y)^2/(2x-y)=(x

计算(4x^2y-9y)/(2x+3)

(4x²y--9y)/(2x+3)=y(2x+3)(2x-3)/(2x+3)=y(2x-3)

已知X.x+y.y-4x+2y+5=0,求4X.X-12X Y+9Y.y的值

∵x²+y²-4x+2y+5=0x²-4x+4+y²+2y+1=0(x-2)²+(y+1)²=0x-2=0y+1=0∴x=2y=-14x&#

4(X+2Y)^2-9(X-Y)^2

你是说分解因式吧,=[2(x+2y)]^2-[3(x-y)]^2=(2x+4y)^2-(3x-3y)^2=[(2x+4y)+(3x-3y)][(2x+4y)-(3x-3y)]=(5x+y)(-x+7y

9(x+2y)^2-4(x-2Y)^2

9(x+2y)^2-4(x-2Y)^2=[3(x+2y)]^2-[2(x-2Y)]^2=[3(x+2y)+2(x-2Y)][3(x+2y)-2(x-2Y)]=(5x+2y)(x+10y)

(2x-y)^2-4(x-y)(x+2y)

4x^2+y^2-4xy-4(x^2-xy+2xy-2y^2)展开化简吧!

4x(y-x)-y^2因式分解

4x(y-x)-y²=4xy-4x²-y²=-(4x²-4xy+y²)=-(2x-y)²很高兴为您解答,【the1990】团队为您答题.请点

已知4x=9y求(1)x+y/y (2)y-x/2x

4x=9yx=9/4*y(1)(x+y)/y=[(9/4)y+y]/y=(9/4+1)y/y=9/4+1=13/4(2)(y-x)/2x=[y-(9/4)y]/[2*(9/4)y]=(1-9/4)y/

化简:(2x-y)²-4(x-y)(x+y)

(2x-y)²-4(x-y)(x+y)=(4x²-4xy+y²)-4(x²-y²)=4x²-4xy+y²-4x²+4y&

9y=3x-(x-1),4(x+y)-(2x+4)=8y

解9y=3x-(x-1)2x-9y+1=0①4(x+y)-(2x+4)=8y2x-4y-4=0②②-①得:5y-5=0∴y=1将y=1代入①得:2x-9+1=0∴x=4∴方程的解为:x=4,y=1

x+2y+4y^2/x-y+4x^y/4y^2-x^2

“4y^2/x-y”应该是“4y^2/x-2y”吧x+2y+4y^2/x-2y+4x^2y/4y^2-x^2=(x+2y)+4y^2/(x-2y)+4x^2y/(2y-x)(2y+x)=(x+2y)+

4x^2+2x-9y^2-3y

4x^2+2x-9y^2-3y=(2x)²+2x+(1/2)²-[(3y)²+3y+(1/2)²]=(2x+1/2)²-(3y+1/2)²=

4(2x+y) -9(x-2y)

4(2x+y)²-9(x-2y)²=[2(2x+y)]²-[3(x-2y)]²=[2(2x+y)+[3(x-2y)][2(2x+y)-3(x-2y)]=(7x-

(x+3y-4)(2x-y)

原式等于2x^2-xy+6xy-3y^2-8x+4y=2x^2+5xy-3y^2-8x+4y

4(x-y)^2-9(x+y)^2因式分解,

4(x-y)^2-9(x+y)^2=[2(x-y)]^2-[3(x+y)]^2=(2x-2y)^2-(3x+3y)^2=(2x-2y+3x+3y)(2x-2y-3x-3y)=-(5x+y)(x+5y)