3x的平方-6x-9-搜答案-智慧作业帮

原式=(x-3)^2)*[(x+3)/(x-3)(x-6)]=(x+3)(x-3)/(x-6)=(x^2-9)/(x-6)

题意是这样的吧：求(x²+9x)/(x²+3x)+(x²-9)/(x²+6x+9)原式=(x²+9x)/(x²+3x)+(x+3)(x-3)

格式有点乱,〖((1-x)/(3-x))^2/((x^2-6x+9)/(9-x^2 ))〗^ ×1/(x^2-2x+1)=〖((1-x)/(3-x))^2/(〖(X-3)〗^2/(

X的平方+3X分之X的平方+9X+X的平方+6X+9分之X的平方-9=x（x＋3）分之（x²＋9x）＋（x＋3）²分之（x＋3）（x-3）==x（x＋3）分之（x²＋9x

(X的平方+9x)/(x的平方+3x)+（x的平方-9)/(x的平方+6x+9)=x(x+9)/x(x+3)+(x+3)(x-3)/(x+3)²=(x+9)/(x+3)+(x-3)/(x+3

=(x+2)(x-1)/(x-3)×(x-3)²/(x+2)=(x-1)(x-3)=x²-4x+3

x的平方-4x+3-(x的平方-6x+9)=(x-1)(x-3)-(x-3)^2=2(x-3)whenx>3,x的平方-4x+3>(x的平方-6x+9)whenx

x的平方-9分之x的平方+2x-3乘x的平方-1分之x的平方-5x+6=(x-3)分之(x-1)乘[(x-1)(x+1)]分之(x-2)(x-3)=(x+1)分之(x-2)

2x(x-3)/(x+3)(x-3)+(x+3)/(x-3)-2(x+3)/(x+3)²=32x(x-3)/(x+3)(x-3)+(x+3)/(x-3)-2/(x+3)=3两边乘以(x+3)

x的平方-6x+9/9-x的平方÷2x-6/x的平方+3x{(x-3)²/[(3-x)(3+x)]}÷{2(x-3)/[x(x+3)]}=[(3-x)/(3+x)]÷{2(x-3)/[x(x

原式=(x-3)/(x²+x)*1/(x-3)²约去x-3=1/[(x-3)(x²+x)]=1/(x³-2x²-3x)

原式=(x+6)(x-3)/[x(x+6)]*1/(x-3)²=1/[x(x-3)]=1/(x²-3x)

因为x^2-x-3=0所以x^2-x=3,x^2=x+3故x(x^2-x)-x(6-x)-9=3x-6x+x^2-9=x^2-3x-9=x^2-x-2x-9=3-2x-9=-2x-6x^2-x-3=0

(x²+6x+9)分之(x-3)+(9-x²)分之x=(x²+6x+9)分之(x-3)-(x²-9)分之x=(x+3)²分之(x-3)-[(x+3)(

原式=(x+1)(x-3)/(x-3)²=(x+1)/(x-3)

原式=x(x-9)/x(x+3)-(x+3)(x-3)/(x-3)²=(x-9)/(x+3)-(x+3)/(x-3)=(x²-12x+27-x²-6x-9)/(x+3)(

(4x+20)(x的平方-6x+9)/(3x-x的平方)(x的平方+2x-15)=4(x+5)(x-3)²/3（3-x）(x-3)(x+5)=-4/3

(9x平方-6x+1)÷(x-2)×(2x-(x)的平方)÷(3x-1)=(3x-1)²÷(x-2)×(2-x)x÷(3x-1)=(3x-1)²÷(3x-1)×(2-x)x÷(x-

原式=x^2+9x/x^2+3x+x^2-9x/x^2+6x+9=2x^2+9x+9很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,