3x-y)的平方-(2x y)的平方-5-搜答案-智慧作业帮

是不是求(x2＋3xy＋2y2)／(x2y+2xy2）,如果是,则[（x+y)2+y(x+y)]／[xy(x+2y)]再化为（x+y)／xy=4／3

-x的平方y-xy平方=-XY(Y+X),再把x+y=3,xy=2代入结果为=-XY(Y+X）=-2乘3=-6

xy(xy+1)+(xy+3)-2(x+y+1/2)-(x+y-1)^2=xy(xy+1)+(xy+1)+2-2(x+y)-1-[(x+y)^2-2(x+y)+1]=(xy+1)^2+2-2(x+y)

=-x-(2y-2+3x)+2(x+4)=-x-2y+2-3x+2x+8=-4x-2y+10

=(x-2y)(x-y)/(x-y)²=(x-2y)/(x-y)再问：做完啊。。。。。。再答：好了呀这个不可以再化简了，是一个最简分式了再问：刚刚不小心题目打掉了，你在看已知Y分之X等于7分

y是多少原式=(x+y)(x-y)/(x-y)²+x(y+3)/x(y+3)=(x+y)/(x-y)+1=(x+y+x-y)/(x-y)=2x/(x-y)=1/(1/2-y)再问：y=3

Y^2(2X+1)(X-3)

楼主是不是把题写错了呀,应该是（X+2)^2+/Y+1/=0吧因为（X+2)^2大于等于0/Y+1/大于等于0所以只有同时为0时,和才为0即X=-2Y=-1带入原式=4

x的平方+3xy+2y的平方除以x的平方y+2xy的平方=(x+2y)(x+y)/xy(x+2y)=12/9=4/3再问：那个再问一下不改变分式的值使分式的分子分母首项系数都是正数-(负7xy/负8z

是3x²y-3xy²+2x²y+2xy²-1=5x²y-xy²-1

（x+y）(x+2y)=x²+xy+2xy+2y²=x²+3xy+2y²

x的平方-2xy/xy-2y的平方＝x(x-2y)/y(x-2y)=x/y

x平方-3xy+2y平方=0(x-2y)(x-y)=0x=2yx=y(1)x=2y则xy分之x平方+y平方的值=((2y)^2+y^2)/(2y*y)=(4y^2+y^2)/(2y^2)=5/2(1)

原式(-xy/3)²*[xy(2x-y)-2x(xy-y²)]=(x²y²/9)(2x²y-xy²-2x²y+2xy²)

M-(2x^2-3xy+xy^2)(-xy)=(2x^2y+xy^2)(x-2y)M=(2x^2y+xy^2)(x-2y)-(xy)(2x^2-3xy+xy^2)=2x^3y-4x^2y^2+x^2y

a-2b=(5x²y-3xy²+4xy)-2(7xy²-2xy+x²y)=5x²y-3xy²+4xy-14xy²+4xy-2x&#

3x²y-{2xy-2(xy-3/2x²y)}+xy=3x²y-{2xy-2xy+3/2x²y}+xy=3x²y-2xy+2xy-3/2x²

答案y的平方+8xy-5x的平方

原式=-x^2+2xy-y^2-2xy+6x^2+6y^2-3xy=5x^2-3xy+5y^2

(x平方+2xy+y的平方）/（x+y)=（x+y)²/(x+y)=x+y