0.49x的平方减去0.04y的平方分解因式-搜答案-智慧作业帮

x的平方减去2x加上y的平方减去6y加上10等于0就是x^2-2x+1+y^2-6y+9=0(x-1)^2+(y-3)^2=0x=1y=32x+3y=11

题目给错了吧,应该为x的平方加上2x加上y的平方减去6y加上10等于0如果是,x^2+2x+y^2-6y+10=0,所以：(x+1)^2+(y-3)^2=0所以：x+1=0且y-3=0两式相加,得到：

x^2+2x+1+y^2-6y+9=0（把10分成1和9,配两完全平方式）(x+1)^2+(y-3)^2=0x+1=0,y-3=0x=-1,y=3x-y=-1-3=-4

x^2-y^2=6(x+y)(x-y)=6因为x-y=3所以x+y=2联立方程组：x-y=3x+y=2解得：x=5/2,y=-1/2

x²-y²=(x-y)(x+y)平方差公式

（x2+y2)2-3(x2+y2)-70=0把x2+y2设为a那就是a2-3a-70=0,是不是简单了（a-10）（a+7）=0a1=10,a2=-7但是这里要知道x2+y2肯定大于0所以x2+y2=

这个代数式：x^2+y^2+x^2-y^2=2x^2

A(1,0)则x=1时y=0所以0=2-m-m²m²+m-2=0(m+2)(m-1)=0m=-2,m=1由韦达定理x1+x2=m/2x1=1x2=m/2-1m=-2,x2=-2m=

6xy^2-9x^2y-y^3=-y(-6xy+9x^2+y^2)=-y(9x^2-6xy+y^2)=-y(3x-y)^2

根号下大于等于0x²-4>=0,x²>=44-x²>=0,x²

如果问题是：1／2（x的平方＋y的平方）－xy=2

2/(x-y)-(x+y)/(x-y)^2=[(2x-2y)-(x+y)]/(x-y)^2=(x-3y)/(x-y)^2

(x^2-4y^)\(x+y)^2乘以2x(x+y)/(x+2y)=2x(x-2y)\(x+y)

x^2-2xy-y^2=0x=(1-根号2)y或x=(1+根号2)y因为x,y为正数所以x=(1+根号2)y(x-y)/(x+y)=根号2-1

x+y-7=-6x^2-x=13y^2-y=13两式相减x^2-y^2-x+y=0(x+y)(x-y)-(x-y)=0(x-y)(x+y-1)=0因为x≠y所以x-y≠0所以x+y-1=0x+y-7=

2x^2+xy-y^2-4x+5y-6=(2x-y)(x+y)-(4x-5y)-6=(2x-y+2)(x+y-3)

(x+y)²(x-y)-(x+y)(x²+y²)=(x+y)[(x-y)(x+y)-(x²+y²)]=(x+y)(x²-y²-x&

-12xy*3x^2y-x^2y*(-3xy)=-36x^3y^2+3x^3y^2=33x^3y^2

=（x-y-4)²

0.49x的平方减去0.04y的平方 分解因式