向一维数组a[10]中输入10个数据

#include#includevoidmain(){\x05inti,j;\x05floatsuma,sumb;\x05floatavga,avgb;\x05intmaxa,maxb;\x05int

OptionExplicitDimarr(100)AsIntegerDimarr1(100)AsIntegerDimiAsIntegerPrivateSubCommand1_Click()Fori=1

//prob.cpp:Definestheentrypointfortheconsoleapplication.//#include"stdafx.h"#include//#includeusingn

main(){inti,t,max=0,min=0,w[10];for(i=0;iw[max])max=i;if(w[i]

#include"stdio.h"#defineN4intmain(){inti,j,k,w=1,p=2;inta[N][N],b[N][N],x[N];for(i=0;i

新的数字放在数组最后向前循环比较大小,进行位置调换亦可如下方式：dimea(5)FORi=1TO4a(1)=17a(2)=36a(3)=45a(4)=65ENDFORb=46FORi=4TO1STEP

#includeintmain(){intarray[10]={0};inti,min;printf("请输入10个数字：\n");scanf("%d",&array[0]);min=arr

#include#defineN20//默认数组大小20intmain(){inta[N],i;doubleave=0;printf("输入20个数\n");for(i=0;i

第1题：PrivateSubCommand1_Click()Dimv(1To20)AsDoubleDimvMaxAsDoubleDimvMinAsDoubleDimiAsLongFori=1To20v

随便写了一下没有测试,应该可以吧,试试,大于平均的最小小于平均的最大intmin,max;intminflag=0;intmaxflag=0b=min=max=cal(平均数);for(i=0;ib)

intk=0,j=14,x;for(inti=0;i

#includeintmain(){inta[10];intb[10];int*pa=a;int*pb=b;intcnt=0;printf("输入:");while(pa-a

#include<stdio.h>void fanxu(int c[], int j);void main(){\x09int 

#includeusingnamespacestd;voidmain(){chara[10];inti,temp;for(i=0;i>a[i];cout

第一题：#includevoidmain(){inta[10]={1,2,3,4,5,6,7,8,9,10},i,max,min;/*初始化的值任意定,只要是在整型范围内都行*/max=a[0];

importjava.util.Scanner;publicclassInputTest{publicstaticvoidmain(String[]args){Scannerin=newScanner

#includeintsearch(intlist[],intn,intx){\x09inti;\x09for(i=0;i

voidmain(){floata[10];float*p=a,max,min,pj=0;inti=0,j;for(;i

#include#include#defineN20voidmain(){inti,k,j,a[N];k=0;printf("Pleaseinputtwentynozeronumbers\n");fo

#includeintmain(){doubled[10],sum=0,ave=0;inti;for(i=0;i