3(x-5)=4(x-1)怎么解
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/16 16:14:37
是这样的:x^5+x^4=x^3(x^2+x)=(x^2+x)[(x^3-1)+1]=(x^2+x)(x^3-1)+x^2+x=[x(x+1)(x-1)](x^2+x+1)+x^2+x=(x^3-x)
设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y
1)(x-3)/(x-2)-(x-5)/(x-4)=(x-7)/(x-6)-(x-9)/(x-8)化简得【(x-3)(x-4)-(x-5)/(x-2)】/【(x-2)(x-4)】=【(x-7)(x-8
再问:额、不懂再答: 再答:后面的看做一个整体再问:好的吧、谢谢大神再答:回来的话,请采纳再问:啊、突然明白了呢。。。
1.3/4x=2x=8/3
x-3/5x=1-3/4(1-3/5)x=1-3/42/5x=1/4x=1/4÷2/5x=5/8
(X+2)/(X+1)-(X+4)/(X+3)=(X+6)/(X+5)-(X+8)/(X+7)(X+1+1)/(X+1)-(X+3+1)/(X+3)=(X+5+1)/(X+5)-(X+7+1)/(X+
x+x^2+x^3+x^4+x^5+x^6+x^7+x^8=(x+x^2+x^3+x^4)+(x^5+x^6+x^7+x^8)=x(1+x+x^2+x^3)+x^5(1+x+x^2+x^3)=(x+x
再问:2x是怎么得来的
3(2x-1)+5(1-2x)+2x+4=06x-3+5-10x+2x+4=0-2x+6=0x=3
2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99
2x²+8x-10-3x+6-4x=2x²+7x-4=7x=11
2x^5-5x^4-x^3+x^2-6x/(x^2+1)=2x^5-5x^4-x^3+x^2-6x/3x=2x^5-5x^4-x^3+x^2-2=2x^3(x^2-3x+1)+x^4-3x^3+x^2
可以设g(x)=(2x-3)^4,h(x)=(x^2+x+1)^5则f(x)=g(x)h(x)f'(x)=g'(x)h(x)+g(x)h'(x)g'(x)=4(2x-3)^3(2-0)=8(2x-3)
首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(
移项,把X项移到左边为3X,常数项移到右边为1,两边同时除以3得X=1/3
x/(x-2)=(x-4)/(x-5)方程两边同乘(x-2)(x-5),得:x(x-5)=(x-4)(x-2)x^2-5x=x^2-6x+8x=8x/(x-3)=(x+1)/(x-1)x^2-x=x^
7x-3(2/3x+1/5x)-(x+2/5x)+2x=5x7x-2x-3/5x-x-2/5x+2x,=5x7x-x=5x6x=5x6x-5x=0x=0再问:大哥=5x怎么求出再问:大哥=5x怎么求出
首先,等式两边不能同时为0..而且x为整数..证明很简单..若x是实数,不是整数,设x的小数部分为k,整数部分x-k=m,则左侧为[(m-1)+k][(m-2)+k][(m-3)+k][(m-4)+k